在Linux上替代_DEBUG

Question

#ifdef _DEBUG
a = "ram";
#else
a = "sam";
#endif

It is working fine in Visual Studio as _DEBUG is defined in pre-processor, whereas it is not working in Linux even though I gave "-g" option while compiling. What would be the alternative for this? I want the same piece of code for both platforms.

Answer 1

The standard macro for this is NDEBUG , though it has the opposite sense of _DEBUG (the N is for "not"). So you can write your code portably like this:

#ifndef NDEBUG
a = "ram";
#else
a = "sam";
#endif

Note how I used #ifndef to negate the conditional. Of course you could write it equivalently as:

#ifdef NDEBUG
a = "sam";
#else
a = "ram";
#endif

If you don't like this, you can also define _DEBUG on Linux by compiling like this:

g++ -g -D_DEBUG ...