用PHP回送表单和输入

Question

It's my first question here and I hope I can get some help.

The code should display the comments present in the database and add an EDIT button if the user that is logged in is the same as the author of the comment.

This is the part of the code that is causing problems.

 if($_SESSION['login_user'] == $row["user"]) 
{
    echo"<form action ='editform.php' method='POST'>";
    echo "<input type='hidden' name='id' value= '". $row["id"] ."'/>";
    echo "". $row["user"] . "". "<br>" . $row["messaggio"] . "<br>". "";
    echo "<input name='submit' type='submit'  value='edit'>". "<hr>";
    echo "</form>";
}

I can not figure out what I am doing wrong. Only the comments and the user are displayed, and no Edit button.

Any idea on what I am doing wrong?

Answer 1

If the form is not being printed to the HTML, it means that:

$_SESSION['login_user'] != $row["user"]

Start from there.

Try using print_r or die to debug the value of the variables.

The submit button is also missing a / at the end, but that is not certainly the reason.

Answer 2

I've copy pasted the code into a blank php-file and removed the if-statement.

It showed up an edit button for me. I think there were errors in your formatting.

I often type code like this, to not have any issues with formatting:

if ($_SESSION['login_user'] == $row['user'] { ?>

    <form>

        <input type="hidden" name="id" value="<?php echo $row['id']; ?>">

        <?php echo $row['user']; ?><br>
        <?php echo $row['message']; ?><br>

        <input name="submit" type="submit" value="edit"><hr>

    </form>

<?php
}

Also, if working with $_SESSION variables, make sure to have session_start() on top of each page where you need to access $_SESSION variables.

Answer 3

I tried with sample data and it works: ;)

<?php
    $u_id = "Rapax_id";
    $user = "Rapax";
    $message = "This is the message!";

    $login_user = "Rapax";



     if($login_user == $user) 
    {
        echo"<form action ='editform.php' method='POST'>";
        echo "<input type='hidden' name='id' value= '". $u_id ."'/>";
        echo "". $user . "". "<br>" . $message . "<br>". "";
        echo "<input name='submit' type='submit'  value='edit'>". "<hr>";
        echo "</form>";
    }
    else
    {
        echo "Your are not Authorized";
    }
?>

Answer 4

   <?php if($_SESSION['login_user'] == $row["user"]) { ?>
   <form action ='editform.php' method='POST'>
   <input type='hidden' name='id' value="<?php echo $row["id"]; ?>" />
   <?php echo $row["user"]; ?>
   <br>
   <?php echo $row["messaggio"]; ?>
   <br>
   <input name='submit' type='submit'  value='edit'>
   <hr>
   </form>   
   <?php } ?>

use this and try..