在不同的目录中获取未知的文件名，php

Question

Here is my directory structure,

C:\xampp\htdocs\..

C:\download\20150923abc.xls  //abc is a random value

how can I attach the file 20150923abc.xls in php?

Also, how to change the filename after I got it?

Thanks.

Answer 1

Use the glob ability to find references all files of type .xls and then you can use the file name references as you wish. This sidesteps the issue of you not knowing the specific file name.

$files = glob("c:/download/*.xls");

This will produce an array of all .xls files with their full filepath. If you wish to rename or attach these files then you can do this using the glob reference:

rename($files[0], "c:/download/somenewname.xls");

etc. Read more at:

PHP Glob Function

EDIT:

From Comment below:

foreach (glob( $old_folder."*.xls") as $filename) 
{
     $names = explode('/', $filename); 
     $just_file_name = end($names); 
     echo $just_file_name . "----\n"; 
     $new_folder = dirname(FILE)."\\prm\\att\\";
      //rename_win($old_folder, $new_folder); 
     rename($filename, $new_folder.$just_file_name); <== this line changed.
}
unset($filename);

To fix the above code in your comment, you need to change the incorrect variables referenced (there was no array $files[0] ) to the ones used in the foreach loop.