将字母输入与c中的整数输入区分开

Question

There are two kinds of input that can be provided:

50
b 2 40

I have to distinguish both the cases and then take further actions accordingly. Here's what I have tried:

char input[100];
fgets(input, 100, stdin);
printf("%s", input);
int count = 0;
char a[3][100];
int j=0, i=0;
while(true){

  a[count][j] = input[i];
  j++; i++;

  if(input[i] == '\n'){
    break;
  }
  if(input[i] == ' '){
    count++;
    j = 0;
    i++;
  }
}
printf("%d\n", count);
printf("%s\n", a[0]);
printf("%s\n", a[1]);
printf("%s\n", a[2]);

For example, input:

b 6767 9090

output:

b 6767 9090
b 6767 9090
2
b����
67670
9090

Can somebody help me on how to do this? I was suggested previously to use fgets. As I am a beginner in C, I am having difficulty figuring out how to achieve this.

Answer 1

遇到空格时，您应该设置'\\0'或null终止符，或者您可以预先将数组的所有元素设置为0或null，如下所示-

char a[3][100] = {0};

Answer 2

另外，如果用户输入的字符串超过三个单词（即count> 2），则该程序将崩溃，因为loop while（true）会一直尝试直到命中\\ n字符。

Answer 3

I found out that the best way to do this would be:

char inp[25];
scanf("%s", inp);
if(inp[0] == 'b'){
  int r, v;
  scanf("%d %d", &r, &v);
}
else{
  int v = atoi(inp);
}