这是在wpf mvvm中显示另一个窗口的最佳方法

Question

Hi I got some problem with navigating windows in wpf mvvm. I got two wpf windows, let's say viewA and viewB. all respective view model are bind to the view using prism prism:ViewModelLocator.AutoWireViewModel="True" .

This is my view.

<Window x:Class="eBriefcase.WPF.Views.CaseHearing"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:prism="http://prismlibrary.com/"
    prism:ViewModelLocator.AutoWireViewModel="True"
    Title="CaseHearing" Height="300" Width="300">
<Grid>

</Grid>

If I want to go to another view, I create new window and use show function in View Model.

ViewB vB_ = new ViewB();
vB_.Show();

when I press show another form button, another duplicate wpf window is open. How can I control it? I just studied WPF for only 10 days. Is it the correct way of navigating between views?

Best Rgds, df

Answer 1

The answer is in your question:

I create new window and use show function

So the new window is shown. You are being confused with the term view . View is not some kind of object in WPF. It's just logical part of MVVM concepts. Objects that you operate are Windows , controls and pages . Looks like you want to use WPF pages as different views of your data. There are plenty of manuals on the net about WPF pages and NavigationService These are keywords that you need.

BTW, answering the question in the header: The best method to open windows is to wrap opening windows into some generic WindowManager and use

new WindowType(){ DataContext = VM }.Show()