test1.java:10: 错误：未报告的异常 IOException； 必须被捕获或声明被抛出 char ch = (char)br.read(); ^

Question

Any help will be appreciated

My code:

   import java.io.*;
   import java.util.Scanner;

class Accept {

public static void main(String args[])
{ 
    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
    System.out.print("Enter: ");
    char ch = br.read();
    System.out.print("Entered is: " + ch);
}

}

Answer 1

Just like the error says, you have to either catch or throw the IOException thrown by mentioned method.

You can throw it by:

public static void main(String args[]) throws IOException
{ 
    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
    System.out.print("Enter: ");
    char ch = (char) br.read();
    System.out.print("Entered is: " + ch);
}

Java tutorials is a good place to start learning about Java Exceptions.

Answer 2

you can also try this:

  public static void main(String[] args) {
      try {
          BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
          System.out.print("Enter: ");
          char ch = (char) br.read();
          System.out.print("Entered is: " + ch);
      }catch(IOException ex) {
        Logger.getLogger(State.class.getName()).log(Level.SEVERE, null, ex);
    }
}