JS如果出现错误，请重试

Question

if function returns error, further code is no longer executing. I need to retry this function until success. How can I do it?

... // API request...

function(error, something) {
    if (!error) {
    something = true;
    // Etc...
    }
    else {
        // Code to try again.
    }
}

Answer 1

I prefer having a function calling it self so you have more freedom

function repeat() {
  repeat()
}

Then you can all kind of tings. Your example would be

const repeat = () => {
    // Your code
    if(error) {
        repeat()
    }
}

If you only run it once, then make a self executing function.

(function repeat() {
    // Your code
    if(error) {
        repeat()
    }
})()

Because we use a function calling it self we can use setTimeout

(function repeat() {
    // Your code
    if(error) {
        setTimeout(() => {
            repeat()
        }, 100)
    }
})()

This makes it possible for the code to have a little break insted of running none stop.

Answer 2

Try this

  do {
    // do your stuff here
  }while(error)

For tour case you can do it like this :

function(error, something) {
    do {
        // do your stuff here
      }while(error)
}

To do what you want until the error become false

Or you can use while

    function(error, something) {
        if(!error){
            // this code is executed once
         }
            while(error){
                // do your stuff here
              }
        }

It will test the error before executing the first time

For more example take a look here

For the last comment you can do it like this (without loop) :

function Test(error, something) {
        if(!error){
            // your code that you want to execute it once
        }
        else {
            // do stuff
            Test(error, something); // re-call the function to test the if
        }
    }