Symfony2显式获取URL的路径信息

Question

Say, I have an URL http://server/mysite/web/app_dev.php/resource/1 . I am doing a GET request and the corresponding action is ResourceController::getAction .

In this controller action if I call $request->getPathInfo() , it gives me /resource/1 .

But in the same controller if I create a Request object with a url of another resource and call getPathInfo() it returns a longer version.

$request = Request::create('http://server/mysite/web/app_dev.php/another_resource/1');
echo $request->getPathInfo();

OUTPUT >>
/mysite/web/app_dev.php/another_resource/1

How is it possible to make getPathInfo() to return only /another_resource/1 in this case?

OR

Anyone can suggest what is the safest way to convert an endpoint URL http://server/mysite/web/app_dev.php/another_resource/1 to /another_resource/1 in Symfony2?

In case you are interested to know why I need this

The controller action is receiving some URLs in request content. The action needs to parse those URLs to recognize the corresponding resource. I am trying to make use to $router->match function to retrieve the parameters from the URL. The match function expects only /another_resource/1 part.

Answer 1

Request::create method create a new request that don't know any information about current request, it return full uri because it not know current script file. try:

$request = Request::create('http://server/mysite/web/app_dev.php/another_resource/1', null, array(), array(), array(), array(
    'SCRIPT_NAME' => $this->get('kernel')->getEnvironment() == 'dev' ? 'app_dev.php' : 'app.php',
    'SCRIPT_FILENAME' => $this->get('kernel')->getEnvironment() == 'dev' ? 'app_dev.php' : 'app.php',
));
echo $request->getPathInfo();