[英]calculate a total using SQL Query
I have a table with 3 attributes: 我有一个具有3个属性的表:
Title TotalNumberOfAuthors TotalNumberOfPublishedAuthors
A 3 1
B 2 2
C 4 2
D 2 1
I am trying to create a query that Displays the Sum of TotalNumberOfPublishedAuthors and the sum of TotalNumberOfNonPublishedAuthors which is (TotalNumberofAuthors - TotalNumberOfPublishedAuthors).. 我正在尝试创建一个查询,该查询显示TotalNumberOfPublishedAuthors的总和和TotalNumberOfNonPublishedAuthors的总和(TotalNumberofAuthors-TotalNumberOfPublishedAuthors)。
This is the query that I have generated, but doesn't display the results as expected: 这是我生成的查询,但未按预期显示结果:
SELECT SUM(Submission.TotalNumberOfPublishedAuthors),
(SUM(Submission.TotalNumberOfAuthors) - SUM(Submission.TotalNumberOfPublishedAuthors)) AS Number_of_Non_Published_Authors
FROM Submission INNER JOIN ((Faculty INNER JOIN School
ON Faculty.FacultyID = School.[FacultyID]) INNER JOIN (Researcher INNER JOIN ResearcherSubmission
ON Researcher.ResearcherID = ResearcherSubmission.ResearcherID)
ON School.SchoolID = Researcher.SchoolID)
ON Submission.SubmissionID = ResearcherSubmission.SubmissionID;
This is the result I am trying to get: 这是我想要得到的结果:
TotalNumberofPublishedAuthors TotalNumberofPublishedAuthors
6 5
SELECT <Column Names>
FROM <Table Name>
UNION ALL
SELECT NULL,SUM(<Column name>),null,sum(<RunningTotal or AnyTotal>)
FROM <Table Name>
If you really have columns in the table [Submission] called [TotalNumberOfPublishedAuthors] and [TotalNumberOfAuthors] as shown then there is no need to join any other tables. 如果您在表[Submission]中确实有名为[TotalNumberOfPublishedAuthors]和[TotalNumberOfAuthors]的列,则无需联接任何其他表。 Just perform the sums as you already have them in the query but without further tables. 只需执行总和即可,因为它们已经存在于查询中,但没有其他表。
MS SQL Server 2014 Schema Setup : MS SQL Server 2014架构设置 :
CREATE TABLE Submission
([Title] varchar(1), [TotalNumberOfAuthors] int, [TotalNumberOfPublishedAuthors] int)
;
INSERT INTO Submission
([Title], [TotalNumberOfAuthors], [TotalNumberOfPublishedAuthors])
VALUES
('A', 3, 1),
('B', 2, 2),
('C', 4, 2),
('D', 2, 1)
;
Query 1 : 查询1 :
SELECT
SUM(Submission.TotalNumberOfPublishedAuthors) AS TotalNumberOfPublishedAuthors
, SUM(Submission.TotalNumberOfAuthors)
- SUM(Submission.TotalNumberOfPublishedAuthors) AS Number_of_Non_Published_Authors
FROM Submission
| TotalNumberOfPublishedAuthors | Number_of_Non_Published_Authors |
|-------------------------------|---------------------------------|
| 6 | 5 |
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.