如何在运行mocha测试后杀死nodemon进程？

Question

I need to have a gulp task that starts the server, runs mocha tests against it and finally closes it. I have the following code:

var mocha = require('gulp-mocha');
var nodemon = require('nodemon');

gulp.task('my-integration-tests', function () {    
  return nodemon({ script: './server.js' })
    .on('start', function () {
      gulp.src(['./mySpecs.spec.js'])
        .pipe(mocha());            
  });    
});

The server is successfully started and the tests are run. However after this the process created by nodemon is still alive. Is there a way to instruct nodemon to close upon completion? Also having the application opening and closing in the same process as the mocha tests is not an option with the current configuration.

---

UPDATE:

Apart from ThomasBromans answer, I came up with this solution which seems to work in my case. Whenever gulp-mocha finishes the tests it will kind of emit an 'end' event. When this happens we only need to emit 'quit' on the child process then kill the main process, like so:

gulp.task('my-integration-tests', function () {    
  var childProc = nodemon({ script: './server.js' });

  childProc.on('quit', function () {
    console.log('event emitted, child process is being killed');
  })

  childProc.on('start', function () {
      gulp.src(['./mySpecs.spec.js'])
        .pipe(mocha())
        .once('end', function () {
          console.log('mocha stuff ended. time to kill processes');
          childProc.emit('quit');
          setTimeout(function () {
            console.log('kill main process');
            process.exit();
          }, 1500);
        });            
  });    
});

Unfortunately I still need the timeout between the child process being killed and the killing of the main process, if I remove the timeout it happens that the child process remains hanging. This solution is of course open to improvements.

Answer 1

You can exit the process with process.exit() . Just add another .pipe . Your task will look like this:

gulp.task('my-integration-tests', function () {    
  return nodemon({ script: './server.js' })
    .on('start', function () {
      gulp.src(['./mySpecs.spec.js'])
        .pipe(mocha())
        .pipe(process.exit());
  });
});

EDIT running tasks in a sequence (I am not sure this works without any changes):

var gulp = require('gulp'),
    mocha = require('gulp-mocha'),
    nodemon = require('nodemon'),
    runSequence = require('run-sequence');

gulp.task('nodemon', function() {
    return nodemon({script: './server.js'});
});

gulp.task('mocha', function() {
    return mocha();
});

gulp.task('stop', function() {
    process.exit();
});

gulp.task('my-integration-tests', function () {    
    runSequence('nodemon',
                'mocha',
                'stop');
});