简体   繁体   English

在 Node.js 中解析 XML

[英]Parsing XML in Node.js

I am working on a Node.js app.我正在开发一个 Node.js 应用程序。 I need to be able to parse a Sitemap.xml file.我需要能够解析 Sitemap.xml 文件。 Currently, I have a file sitemap that looks like this:目前,我有一个文件站点地图,如下所示:

<?xml version="1.0" encoding="utf-8"?>

<urlset xmlns="http://www.sitemaps.org/schemas/sitemap/0.9" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"   xsi:schemaLocation="http://www.sitemaps.org/schemas/sitemap/0.9 http://www.sitemaps.org/schemas/sitemap/0.9/sitemap.xsd">

  <url>
    <loc>http://www.example.com</loc>
    <lastmod>2014-03-05</lastmod>
    <changefreq>monthly</changefreq>
  </url>

  <url>
    <loc>http://www.example.com/contact</loc>
    <lastmod>2014-03-05</lastmod>
    <changefreq>never</changefreq>
  </url>

  <url>
    <loc>http://www.example.com/about</loc>
    <lastmod>2015-03-01</lastmod>
    <changefreq>monthly</changefreq>
  </url>
</urlset>

I am trying to parse this xml file and load it into my JavaScript class, which looks like this:我正在尝试解析此 xml 文件并将其加载到我的 JavaScript 类中,如下所示:

class SiteUrl {
  constructor() {
    this.loc = '';
    this.lastMod = null;
    this.changeFreq = 'never';
  }

  static loadFromSitemap(sitemapPath) {

  }
}

Coming from a C# background, I know I could just do this:来自 C# 背景,我知道我可以这样做:

public static List<SiteUrl> LoadFromSitemap(string sitemapPath)
{
  // Load the sitemap into memory
  XDocument sitemap = XDocument.Load(sitemapPath);

  // Get the posts from the sitemap.
  List<SiteUrl> posts = (from post in sitemap.Root.Elements(ns + "url")
                         where ((string)post.Element(ns + "loc"))
                         select new SiteUrl(post)).ToList();

  return posts;
}

I'm not sure how to read and parse Xml in the Node world though.不过,我不确定如何在 Node 世界中读取和解析 Xml。

You may try this npm module:你可以试试这个 npm 模块:

https://github.com/Leonidas-from-XIV/node-xml2js https://github.com/Leonidas-from-XIV/node-xml2js

It gets the job done and builds a nice JavaScript object它完成了工作并构建了一个不错的 JavaScript 对象

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM