正则表达式以匹配同一单词的不同版本

Question

I am trying to get a regular expression to match different versions of the same word.

for example:

If I have jQuery,jquery,JQUERY,Jquery -> they should all be matched and total match count should be 4. I tried:

((jquery?)||(jQuery?)||(JQUERY?)||(Jquery))

but it gives me each word count individually.(ie jquery:1, jQuery:1, JQUERY:1, JQuery:1)

I need jquery:4

My whole code:

var wordMatch = /((react?)|(angular?)|(javascript?)|(node?)|(mongo ?)|((jquery?)||(jQuery?)||(JQUERY?))|(backbone?))/gmi;

Answer 1

First, case insensitive matching is what the i flag is for, and you're already using that. /jquery/i will catch both jquery and jQuery , so you don't need so many options in your regex.

Also, it's not clear what you're trying to do with the ? s, but it seems wrong. ? makes the preceding character or group optional, so /jquery?/ matches both jquery and jquer - probably not what you want.

Answer 2

I think you're looking for

/(string)/gi

This will return all matches of "string" in the same group, not caring about casing.