[英]In Ubuntu, how do I make an alias inside a bash for loop?
I have a script to help me with testing concurrency. 我有一个脚本可以帮助我测试并发性。 I use screen to run a bunch of things at once. 我使用屏幕一次运行一堆东西。 But within all that, I can't figure out how make an alias (or function?) using the for $i variable. 但是,在所有这些之中,我不知道如何使用for $ i变量创建别名(或函数?)。
#!/bin/bash
# alias p='. ./p.sh'
# Run a bunch of apps in separate screens.
export NUM_MUS=3
for (( i = 1; i <= $NUM_MUS; ++i ))
do
echo $i
cd ~/mutest/mu$i
screen -mS mu$i -h 10000 ./app
# How do I make an alias to let me easily access each screen?
# None of these work.
#
# alias mu$i='screen -dr mu$i'
# eval
# function mu$i () { screen -dr mu$i }
# ^AD to get out
done
# Have a way of killing them all.
function mustop ()
{
for (( i = 1; i <= $NUM_MUS; ++i ))
do
screen -r mu$i -X quit
done
screen -ls
}
Please note that I am NOT asking about taking parameters. 请注意,我并不是在询问参数。 I don't want parameters ... unless there IS a way to make it work with parameters? 我不想要参数...除非有一种方法可以使其与参数一起使用?
... ...
Okay, I can add this line, and it'll work "good enough" 好的,我可以添加这一行,它将“足够好”地工作
function mu { screen -dr mu$1 }
But it still doesn't answer my question of using for loop variables to make a buncha aliases/functions. 但是它仍然不能回答我使用for循环变量来创建Bunka别名/函数的问题。 I'm not saying that's this is smartest way to do things, but if I did want to do this, how would I do it? 我并不是说这是最聪明的做事方式,但是如果我确实想这样做,我将如何做?
Variables are expanded inside double quotes, not inside single quotes. 变量在双引号内扩展,而不在单引号内扩展。
alias mu$i="screen -dr mu$i"
Also, make sure you run the script using source scriptname
, so the aliases will be defined in your original shell, not just the shell executing the script. 另外,请确保使用source scriptname
运行脚本,以便别名将在原始外壳程序中定义,而不仅仅是在执行脚本的外壳程序中定义。
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