[英]Repeating an Exception
I am using an exception in my code below. 我在下面的代码中使用异常。 I want to be able to repeat the question until they enter the correct value which is a double or int value.
我希望能够重复这个问题,直到他们输入正确的值,该值是double或int值。 My problem is at when I ask for a value the second time.
我的问题是第二次要求输入值时。 What should I change or use to fix this?
我应该更改或使用什么来解决此问题?
do{
try{
System.out.println("Enter number");
number = Double.parseDouble(br.readLine());
} catch(Exception ex) {
System.out.println(ex +"\nEnter an int or double value");
number = Double.parseDouble(br.readLine());
}
} while(false);
Output: 输出:
Enter number
qwe
java.lang.NumberFormatException: For input string: "qwe"
Enter an int or double value
we
Exception in thread "main" java.lang.NumberFormatException: For input string:
"we"
at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1241)
at java.lang.Double.parseDouble(Double.java:540)
at practicedd.PracticeDD.main(PracticeDD.java:38)
Java Result: 1
Your second parseDouble is not in a try/catch, so nothing gets caught. 您的第二个parseDouble不在try / catch中,因此不会被捕获。 Also, your while(false) will only let this execute the first time.
同样,您的while(false)将只让它第一次执行。 Does this work for you?
这对您有用吗? Also, you could do a while(true) and break after the parseDouble.
另外,您可以执行一会儿(true)并在parseDouble之后中断。
Double number = null;
do{
try{
System.out.println("Enter number");
number = Double.parseDouble(br.readLine());
}catch(Exception ex){
System.out.println(ex +"\nEnter an int or double value");
}
}while(number==null);
} } }}
Your code is almost right. 您的代码几乎是正确的。 First, you need to change the condition of the
while
loop, and also, you need to break out of it 首先,您需要更改
while
循环的条件,并且还需要打破它
do{
try{
System.out.println("Enter number");
number = Double.parseDouble(br.readLine());
break;
} catch(Exception ex) {
System.out.println(ex +"\nEnter an int or double value");
number = Double.parseDouble(br.readLine());
}
} while(true);
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