帐户激活，CodeIgniter

Question

I want to create an account activation where after registering, a link would be sent to an administrator (or one) email whereby the admin just has to click that link to activate that account.

I have the registration and login working. I'm using MySQL Workbench and have a "flag" or rather just a field in my accounts table (named user_login ) to tell whether the account is enabled or disabled, which is disabled by default after registration.

I am stuck and sending a link through email, I'm not sure where to begin. That link that I want to send would contain a random string and would be sent to the admin, say abc/123/random?stringis=1234 . Then the admin would just have to open his email and click on the string and then that specific user's account would be activated. I found this and this but that's just for how to send a link through email.

I don't have an idea on the logic. Do I create a function whereby the link would go directly to the function and from there, it would change the value in my table to enabled or whatever I call it so that the user's account is counted as activated? Do I need to create a new field to match the random generated string then?

Main idea is I'm trying to do like those typical sites whereby a link would be sent to the user to activate the account once he/she clicks it in the email, but this time just to a specific email which is the admin's.

EDIT:

In controller

public function activate_user($activation_code)
{
    $result = $this->home_model->activate($activation_code);

    if($result != FALSE)
    {
        echo "You have activated :".$result[0]->user_id.".";
    }
    else
    {
        echo "Activation failed, something went wrong.";
    }
}

In Model:

public function activate($activation_link)
{
    $this->db->select('*');
    $this->db->from('user_login');
    $this->db->where('activation_link', $activation_link);
    $query = $this->db->get();

    if($query->num_rows() == 1)
    {
        return $query->result();
    }
    else
    {
        return FALSE;
    }
}

Answer 1

为此，当用户在站点中注册时，您需要在表中添加一个称为activation_link字段，然后生成随机字符串，并将其存储在activation_link然后将链接发送给用户，以便一旦用户返回，然后检查链接并激活该用户。

Answer 2

First

Database add two column

• activation_token{varchar|255}
• activation_time{datetime}

After registration Success

• add some randome has into activation_token(md5 or sha1(up to you))
• add time if registration using Current timestamp(now())

Link

link should be I strongly prefer userid in activation url because it's remove the link duplication. http://sitename.com/activation/ {user_id}/{hash}

in controller

public function activation($user_id,$hash)
{

  $timeOfexpiration = 3600;

  $data = $this->model->get_data($id,$hash);

  if(!$data)
  {
    return false
  }

    //if user found 
    //check expiration of linke
    //like

  if($data['activation_time']+$timeOfexpiration < now())
  {
    return true;
  }
  else
  {
    return false;
  }

}