无法显示来自其他div中搜索的Mysql搜索结果

Question

I am trying to display MySQL results (with and without a search) using three divisions. 我试图使用三个划分来显示MySQL结果（有和没有搜索）。 Div 1 has radio buttons for selecting the viewing the results. 第1分区具有用于选择查看结果的单选按钮。 Div 2 has a text that states all members are displayed, a text search box for Name, and a drop-down menu for Type. 第2区的文字说明所有成员均已显示，名称的文字搜索框和类型的下拉菜单。 The results of the search are displayed in Div 3. 搜索结果显示在Div 3中。

When All Members is selected the text "Display All Members" shows in Div 2 and the correct data is displayed in Div 3 (works correctly). 选择所有成员后，文本“显示所有成员”将显示在Div 2中，并且正确的数据将显示在Div 3中（正常工作）。 When the Name radio button is selected the correct text search box displays in Div 2 but I receive the following errors in Div 3: 选择“名称”单选按钮后，正确的文本搜索框会在第2分区中显示，但在第3分区中会收到以下错误消息：

Warning: mysqli_query(): Couldn't fetch mysqli in /home/desgar20/elrenochamber.com/member_dir_test2.php on line 171 警告：mysqli_query（）：无法在第171行的/home/desgar20/elrenochamber.com/member_dir_test2.php中获取mysqli。

Warning: mysqli_error() expects exactly 1 parameter, 0 given in /home/desgar20/elrenochamber.com/member_dir_test2.php on line 173 Could not access database: 警告：mysqli_error（）恰好需要1个参数，第173行的/home/desgar20/elrenochamber.com/member_dir_test2.php中给定的0个参数无法访问数据库：

If I enter text into the search box and submit, Div 2 and Div 3 go blank 如果我在搜索框中输入文本并提交，则Div 2和Div 3变为空白

I am using javascript to show/hide the divisions and php for the search. 我正在使用javascript显示/隐藏除法和php进行搜索。

I have searched for answers but have not found anything to resolve this issue. 我已经搜索了答案，但未找到任何解决此问题的方法。 I don't know what I am missing. 我不知道我在想什么。 Help- -need advice. 帮助-需要建议。

        <style type="text/css">
            .box {
                display: none;
            }
        </style>

        <script type="text/javascript">
            //Show or application part based on selection 
            $(document).ready(function(){
                $('input[type="radio"]').click(function(){
                    if($(this).attr("value")=="all"){
                        $(".box").not(".all").hide();
                        $(".all").show();
                        $(".all_listing").show();
                    }
                    if($(this).attr("value")=="name"){
                        $(".box").not(".name").hide();
                        $(".name").show();
                        $(".all_name").show();
                    }
                    if($(this).attr("value")=="type"){
                        $(".box").not(".type").hide();
                        $(".type").show();
                        $(".all_type").show();
                    }
                });
            });
        </script>
    </head>

    <body>
        <?php
            require_once 'php/dbconnect.php';   // Connect to database
            $connection = db_connect();
        ?>


        <div id="container">

            <div id="service">

                <div id="web">
                    <img width="150px" src="images/search1.png" />
                    <h3>Member <strong><span class="green">Directory</span></strong></h3>
                    <strong>View Members By:</strong><br /><br />
                    <div id="sortOptions">
                        <label><input type="radio" name="sortRadio" value="all"> All Members</label><br />
                        <label><input type="radio" name="sortRadio" value="name"> Name</label><br />
                        <label><input type="radio" name="sortRadio" value="type"> Type</label>
                    </div><!-- sortOptions -->
                </div><!-- end web -->

                <div id="vector">

                    <div class="all box">
                        <h3>Display <strong><span class="green">All Members</span></strong></h3>
                        <p>All Members Displayed</p>
                    </div><!-- all box -->

                    <div class="name box">
                        <h3>Display by <strong><span class="green">Member Name</span></strong></h3>
                        <p><form name="namesearch" method="post" action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>"> 
                            Name:&nbsp;&nbsp;<input type="text" name="find">
                            <input type="submit" name="search" value="Search Names">
                        </form></p>
                    </div><!-- name box -->

                    <div class="type box">
                        <h3>Display by <strong><span class="green">Member Type</span></strong></h3>
                        <p><form action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>" method="post">
                            Type:&nbsp;&nbsp;<select name="type" id="type">
                            <option value="">-- Select A Type --</option>
                            <?php
                                $query = "SELECT * FROM select_type";   //create type drop-down menu
                                $result = mysqli_query($connection, $query); 
                                while ($line = mysqli_fetch_array($result)) { 
                                echo "<option value='". $line['type'] ."'>". $line['type']."</option>";
                                } 
                            ?> 
                            </select>
                            <input type="submit" name="searchType" value="Search Types">
                        </form>
                    </div><!-- type box -->

                </div><!-- end vector -->

            </div><!-- end service-->

            <div id="media" class="group">

                <div class="all_listing box">
                    <p>Directory Listing</p>
                    <!-- Start Directory Listing -->
                    <?php
                        $sql = "SELECT * FROM members ORDER BY name";   // Database query and results
                        $result = mysqli_query($connection, $sql);
                        while($row = mysqli_fetch_array($result)) {
                            // Check record for website
                            if ($row['web']!== "") {
                                echo "<a target=blank href=". $row['web'] . ">" .$row["name"] . "</a><br> " .
                                "". $row["type"] . "<br>" .
                                "Address: " . $row["physicaladdress"] . "<br>" .
                                "Phone: " . $row["phone"] . "<br>" . "<hr>";
                            }
                            else {
                                echo $row["name"]. "<br> " .
                                "". $row["type"] . "<br>" .
                                "Address: " . $row["physicaladdress"] . "<br>" .
                                "Phone: " . $row["phone"] . "<br>" . "<hr>";
                            }
                        }
                        $connection->close();
                    ?>
                </div><!-- all_listing box -->

                <div class="all_name box">
                    <p>Results based on Name Search</p>
                    <?php
                        if (isset($_POST['search'])) {  // Has "Select Names button ben pushed
                            $find = $_POST['find'];
                            $sql = "SELECT * FROM members WHERE name LIKE '%" . $find . "%' ";
                            $result = mysqli_query($connection, $sql);
                            if(! $result) {
                                die ('Could not access database: ' . mysqli_error());
                            }
                            while($row = mysqli_fetch_array($result)) {
                                // Check record for website
                                if ($row['web']!== "") {
                                    echo "<a target=blank href=". $row['web'] . ">" .$row["name"] . "</a><br> " .
                                    "". $row["type"] . "<br>" .
                                    "Address: " . $row["physicaladdress"] . "<br>" .
                                    "Phone: " . $row["phone"] . "<br>" . "<hr>";
                                }
                                else {
                                    echo $row["name"]. "<br> " .
                                    "". $row["type"] . "<br>" .
                                    "Address: " . $row["physicaladdress"] . "<br>" .
                                    "Phone: " . $row["phone"] . "<br>" . "<hr>";
                                }
                            }
                        }
                    ?>
                </div><!-- all_name box -->
    </body>
</html>

I modified the code as recommendation but still receive the same errors as mention above. 我将代码修改为建议，但仍然收到与上述相同的错误。 Here is the area that I am having difficulty with: 这是我遇到困难的领域：

This is the division (div 1) that will display the search option in div 2: 这是将在div 2中显示搜索选项的部门（div 1）：

<div id="web">
    <div id="sort_options">
        <label><input type="radio" name="sortRadio" value="name"> Name</label><br />
    </div><!-- sort_options -->
</div><!-- end web -->

This is the search feature for div 2: 这是div 2的搜索功能：

<div class="name box">
    <form name="namesearch" method="post" action="<?php echo htmlentities($_SERVER['PHP_SELF']);?>"> 
        Name:&nbsp;&nbsp;<input type="text" name="find">
        <input type="submit" name="search" value="Search Names">
    </form></p>
</div>

This is the php code in div 3 to run the query with input from div 2: 这是div 3中的php代码，可使用div 2的输入来运行查询：

<div class="all_name box">
<?php
if (isset($_POST['search'])) 
{   
    $find = $_POST['find'];
    $sql = "SELECT * FROM members WHERE name LIKE '%" . $find . "%' ";
    $result = mysqli_query($connection, $sql);

    if ( $result == false ) 
    {
        echo ("Error description: " . mysqli_error($connection));
    }
    else
     {
        while($row = mysqli_fetch_array($result))
        {
            // Check record for website
            if ($row['web']!== "") 
            {
                echo "<a target=blank href=". $row['web'] .">" .$row["name"] . "</a><br> " .
                "". $row["type"] . "<br>" .
                "Address: " . $row["physicaladdress"] . "<br>" .
                "Phone: " . $row["phone"] . "<br>" . "<hr>";
            }
            else
            {
                echo $row["name"]. "<br> " .
                "". $row["type"] . "<br>" .
                "Address: " . $row["physicaladdress"] . "<br>" .
                "Phone: " . $row["phone"] . "<br>" . "<hr>";
            }
        }
    }
}
    ?>
</div>

What am I doing wrong here? 我在这里做错了什么？

Answer 1

Change this snippet: 更改此代码段：

$sql = "SELECT * FROM members ORDER BY name";   // Database query and results
$result = mysqli_query($connection, $sql);
while($row = mysqli_fetch_array($result)) {

to at least 至少

$sql = "SELECT * FROM members ORDER BY name";   // Database query and results
$result = mysqli_query($connection, $sql);
while($result !== false && $row = mysqli_fetch_array($result)) {

Reason: If your query is faulty, $result will have the value false which will cause the given error. 原因：如果查询错误，则$result的值将为false ，这将导致给定的错误。

Better code would be like this: 更好的代码是这样的：

$sql = "SELECT * FROM members ORDER BY name";   // Database query and results
$result = mysqli_query($connection, $sql);

if ( $result == false )
{
      // handle error with mysqli_... functions
}
else
{
     while($row = mysqli_fetch_array($result)) {
     ...

As always: take the error as standard, success is the exception! 一如既往：以错误为标准，成功是例外！

无法显示来自其他div中搜索的Mysql搜索结果

问题描述

1 个解决方案

解决方案1
0 2015-09-30 21:46:07

无法显示来自其他div中搜索的Mysql搜索结果

问题描述

1 个解决方案

解决方案1 0 2015-09-30 21:46:07

解决方案1
0 2015-09-30 21:46:07