如何在Java中没有特定节点的情况下读写XML文件

Question

I am trying to read an XML File and write a new XML file without the first node(root element) and the second node. 我正在尝试读取XML文件并编写一个没有第一个节点（根元素）和第二个节点的新XML文件。 Here an example.. 这是一个例子。

I got this: afile.xml 我得到了：afile.xml

<soap:Envelope>
 <soap:Body>
  <note>
      <to>Tove</to>
      <from>Jani</from>
      <heading>Reminder</heading>
      <body>Don't forget me this weekend!</body>
  </note>
  </soap:Body>
</soap:Envelope>

and want this : bfile.xml 并想要这个：bfile.xml

<note>
  <to>Tove</to>
  <from>Jani</from>
  <heading>Reminder</heading>
  <body>Don't forget me this weekend!</body>
</note>

Answer 1

One way is to use XSLT, for instance XSLT 2.0 can do it with a simple stylesheet 一种方法是使用XSLT，例如XSLT 2.0可以使用简单的样式表来实现

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="2.0">

<xsl:template match="/">
  <xsl:copy-of select="//note" copy-namespaces="no"/>
</xsl:template>

</xsl:stylesheet>

You need to use an XSLT 2.0 processor like Saxon 9 to run the code given above. 您需要使用像Saxon 9这样的XSLT 2.0处理器来运行上面给出的代码。

If you don't know the name of the element you want to copy then using <xsl:copy-of select="/*/*/*" copy-namespaces="no"/> instead of <xsl:copy-of select="//note" copy-namespaces="no"/> should do. 如果您不知道要复制的元素的名称，则使用<xsl:copy-of select="/*/*/*" copy-namespaces="no"/>代替<xsl:copy-of select="//note" copy-namespaces="no"/> 。

Answer 2

Try the following ... 尝试以下方法...

import java.util.Map;

import cjm.component.cb.map.ToMap;
import cjm.component.cb.xml.ToXML;

public class NoteExtract
{
public static void main(String[] args)
{
    try
    {
        String xml = "<soap:Envelope><soap:Body><note><to>Tove</to><from>Jani</from><heading>Reminder</heading><body>Don't forget me this weekend!</body></note></soap:Body></soap:Envelope>";

        Map<String, Object> map = new ToMap().convertToMap(xml);

        Map<String, Object> mapEnvelope = (Map<String, Object>) map.get("soap:Envelope");

        Map<String, Object> mapBody = (Map<String, Object>) mapEnvelope.get("soap:Body");

        String extractedXML = (new ToXML().convertToXML(mapBody, true)).toString();

        System.out.println("Extracted XML: " + extractedXML);
    }
    catch (Exception e)
    {
        e.printStackTrace();
    }
}
}

Output: 输出：

 -------- XML Detected -------- 
 -------- Map created Successfully -------- 
 -------- Map Detected -------- 
 -------- XML created Successfully -------- 
Extracted XML: <note><to>Tove</to><body>Don't forget me this weekend!</body><from>Jani</from><heading>Reminder</heading></note>

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如何在Java中没有特定节点的情况下读写XML文件

问题描述

2 个解决方案

解决方案1
1 已采纳 2015-10-01 09:02:21

解决方案2
0 2015-10-03 15:14:20

如何在Java中没有特定节点的情况下读写XML文件

问题描述

2 个解决方案

解决方案1 1 已采纳 2015-10-01 09:02:21

解决方案2 0 2015-10-03 15:14:20

解决方案1
1 已采纳 2015-10-01 09:02:21

解决方案2
0 2015-10-03 15:14:20