[英]Getting the process id of a current process without unistd.h
I'm working on a deadlock detection algorithm and I'm only given kernel level libraries, ie #include <linux/somelibrary>
and nothing else. 我正在研究死锁检测算法,我只给了内核级库,即
#include <linux/somelibrary>
,没有别的。 Are there kernel-level facilities that will allow me to get the pid of the current process similar to getpid()
of unistd.h
? 是否有内核级设施允许我获取当前进程的pid类似于
unistd.h
getpid()
?
I did some quick research and I found the answer. 我做了一些快速的研究,我找到了答案。 Thanks so much for your direction.
非常感谢你的指导。 The quick code I used was:
我使用的快速代码是:
printf("My current process id/pid is %d\n", current->pid);
Thanks again! 再次感谢!
This question makes little sense. 这个问题没什么意义。
Are you writing kernel-based code? 你在编写基于内核的代码吗? In which case you can get the pid of the current task by using the "current" macro which points to the current task's task struct (which contains a member with the pid).
在这种情况下,您可以使用“当前”宏来获取当前任务的pid,该宏指向当前任务的任务结构(其中包含具有pid的成员)。 That would only work if your kernel code is running in a context where a "current task" makes sense (ie not an interrupt, tasklet etc).
只有当你的内核代码在“当前任务”有意义的上下文中运行时(即不是中断,tasklet等),这才有效。
If you're writing userspace code, there should be no reason you can't call getpid, which is a library call from the C library defined in unistd.h (or something it includes), which makes the system call. 如果你正在编写用户空间代码,那么你就没有理由不能调用getpid,这是一个来自unistd.h(或它包含的东西)中定义的C库的库调用,这会调用系统。 If there is such a reason, please explain it.
如果有这样的原因,请解释一下。
Making a system call in Linux isn't particularly difficult, but does involve architecture-specific code that you don't want to write. 在Linux中进行系统调用并不是特别困难,但确实涉及您不想编写的特定于体系结构的代码。
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