将标签的innerhtml传递给PHP中的变量

Question

I want to pass the inner html of a label in HTML form to a variable in PHP via POST method. but I don't know how to do so. Here is my code .

    <select id="ops" name="select" onChange="myfunction(this)">

                    <option>PIck item </option>
                    <option value="pepsi">pepsi</option>
                    <option value="coke">coke</option>
                    <option value="fanta">Fanta</option>

    </select><br><br>


<label id="lb" style="display:none" >Qty</label>

<input type="text" name='qtytext' id="num" style="display:none" placeholder="Quantity" onKeyUp="return validateform()"  onSelect="return validateform()" onFocus="myfun2()" required/ >


<label id="lb2" style="display:none" name='price' >  </label>

I want to pass the innerHTML of the above Label to a variable in PHP. InnerHtml has been already set by JS .

Answer 1

When updating innerHTML of label, put the value in a hidden form input. And, finally post the form to the server.

Answer 2

If you set the label via JS, you should set the value of another input field in the form simultaneously:

<form>
  <input type="hidden" name="labelContent" value="theValueToSet" />
</form>

Answer 3

考虑使用表单或 AJAX 发布值并通过var_dump( $_POST );在您的操作页面上获取这些值var_dump( $_POST );