[英]“Using” is not solving the “hides virtual function” warning
I have been googling high and low and can't find a solution that will remove the warning, even when I use the using
directive. 我一直在搜寻谷歌,即使我使用
using
指令,也找不到能消除警告的解决方案。
class TShowException_Form : public TForm {
__published: // IDE-managed Components
TButton *Send_Button;
TButton *Cancel_Button;
TLabel *Message_Label;
private: // User declarations
using TCustomForm::ShowModal;
//using TForm::ShowModal;
public: // User declarations
__fastcall TShowException_Form(TComponent* Owner);
int __fastcall ShowModal(System::Sysutils::Exception *E);
};
I want to hide the original virtual int __fastcall ShowModal(void)
and expose a new one taking an Exception parameter. 我想隐藏原始的
virtual int __fastcall ShowModal(void)
并公开一个带有Exception参数的新virtual int __fastcall ShowModal(void)
。
But it still complaints on "hides virtual function": 但是它仍然抱怨“隐藏虚拟功能”:
[bcc32 Warning] TShowExceptionForm.h(32): '_fastcall TShowException_Form::ShowModal(Exception *)' hides virtual function '_fastcall TCustomForm::ShowModal()'
I have also tried using TForm::ShowModal;
我也尝试过
using TForm::ShowModal;
but with the same result. 但结果相同。 Any ideas of how to solve this warning?
关于如何解决此警告的任何想法?
EDIT 编辑
I found out that it works perfectly well if I override the show()
method instead: 我发现,如果我改用
show()
方法,则效果很好:
class TShowException_Form : public TForm {
__published: // IDE-managed Components
TButton *Send_Button;
TButton *Cancel_Button;
TLabel *Message_Label;
private: // User declarations
using TForm::ShowModal;
using TForm::Show;
public: // User declarations
__fastcall TShowException_Form(TComponent* Owner);
int __fastcall Show(System::Sysutils::Exception *E);
};
So why isn't it working with ShowModal()
? 那么为什么它不能与
ShowModal()
呢?
You must declare overloaded version as virtual
too: 您还必须将重载版本声明为
virtual
版本:
virtual int __fastcall ShowModal(System::SysUtils::Exception * E);
Does not know if C++Builder supports C++11, but if it does, try also to delete
overload which you want to hide: 不知道C ++ Builder是否支持C ++ 11,但是如果支持,还尝试
delete
要隐藏的重载:
virtual int __fastcall ShowModal() = delete;
instead of placing it into private section. 而不是将其放在专用部分。
bcc32 is, in many respects, not very compliant with the C++ standard. 在许多方面,bcc32与C ++标准不太兼容。 Whenever I find myself asking, "Why does this technique that I think should work in C++ not work in bcc32?", I usually assume it's yet another compiler bug.
每当我问自己“为什么我认为应该在C ++中使用的这项技术为什么不能在bcc32中使用?”时,我通常会认为这是另一个编译器错误。
The fact that Show
works while ShowModal
doesn't is interesting. Show
有效而ShowModal
无效的事实很有趣。 Looking at Vcl.Forms.hpp shows the difference: Show
is defined with HIDESBASE
(a macro that expands to __declspec(hidesbase)
). 查看Vcl.Forms.hpp可以看到以下区别:
Show
是使用HIDESBASE
定义的(扩展为__declspec(hidesbase)
的宏)。
Adding HIDESBASE to your ShowModal should work as well. 将HIDESBASE添加到ShowModal应该也可以正常工作。 You may also have to declare a virtual destructor, if you don't already have one, due to bcc32 compiler weirdness.
由于bcc32编译器很怪异,您可能还必须声明一个虚拟析构函数(如果还没有的话)。
virtual __Fastcall ~TShowException_Form() {}
You get the warning because what you are trying to do happens very often by mistake and is a serious and very hard to find bug if it is done by mistake. 之所以会发出警告,是因为您尝试做的事情经常会错误地发生,并且如果错误地做的话,这是一个严重且很难发现的错误。 Maybe you should use a different name.
也许您应该使用其他名称。
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