在不使用数据库 ID 的情况下捕获动态页面

Question

This is my content.php . I want to show sectors/sector_id=1.php if some one click one my side bar sectors/sector_id=1.php then sector pass an ID 1 then it shows some content then another menu then it goes to another page, but it shows only one page sector_id=0.php and when ID is 1 or 2 it shows sector_id=0.php this page:

<?php
    if($id==1) include('sectors/sector_id=1.php');
    if($id==2) include('sectors/sector_id=0.php');
?>

This is my side bar

<ul id="sector-nav" class="nav"> 
    <li >
        <!--<a href="&Itemid=&sector_id=1">Fibre</a>-->
        <a href="sectors.php?<?php echo $id=1; ;?>">Fibre</a>
    </li>
    <li >
        <!--<a href="&Itemid=&sector_id=2">Hand Protection</a>-->
        <a href="sectors.php?<?php echo $id=2; ?>">Hand Protection</a>
    </li>
    <li >
        <!--<a href="&Itemid=&sector_id=3">Purification Products</a>-->
        <a href="sector_id=3.html">Purification Products</a>
    </li>
    <!-- others <li>'s -->
</ul>

Answer 1

The problem here is how you're trying to pass the variables. If you're Link is:

<a href="sectors.php?1">Fibre</a>

This will not get through to your PHP the way you want. I would advise creating the link like so:

<a href="sectors.php?id=1">Fibre</a>

When this link is followed, sectors.php will be able to get that value from $_GET['id'] variable. You can then do:

<?php
if(isset($_GET['id'])){
    include('sectors/sector_id=' . $_GET['id'] . '.php');
}
?>

Now, if you do something like:

<a href="sectors.php?1">Fibre</a>

This can be used too, but will generate a NULL value at the index called 1, $_GET['1'] . So you could grab the Key versus the value if you wanted.