PHP代码中的nl2br不会生成新行

Question

I'm trying to print two 3-digit random numbers one below the other. I've tried a bunch of functions but it does not seem to output a new line and the second random number.

Code is as follows:

<?php
echo "<h1><center>Random php</center></h1>"; 
echo rand(100,990);
echo nl2br(“\n”,false);
echo rand(100,990);
?>

The output is as follows on the browser.

Random php

698 Fatal error: Undefined constant '“\\nâ€' in /Volumes/Macintosh Media/code/random/main.php on line 4

Answer 1

You are using curly quotes instead of the ASCII double-quote character in nl2br :

echo nl2br(“\n”,false);

instead of

echo nl2br("\n",false);

PHP does not know what to do with the curly quotes and is trying to parse the entire thing ( “\\n” ) as the name of a constant (which of course does not exist).

In any case, it is much simpler to do as Harshit Shrivastava suggests and print a <br> rather than use the nl2br() function here.

Answer 2

nl2br insert line breaks where newlines (\\n) or carriage (\\r) occur in the string:

<?php
echo nl2br("One line.\nAnother line.");
?>

This will output as folows

One line.
Another line.

For your code to work, use <br>

<?php
echo "<h1><center>Random php</center></h1>"; 
echo rand(100,990);
echo "<br>";
echo rand(100,990);
?>

Check the link for more on this

Answer 3

You should use <BR> .

<?php
echo "<h1><center>Random php</center></h1>"; 
echo rand(100,990);
echo "<BR>";
echo rand(100,990);
?>

nl2br is use to convert \\n to <BR>

Answer 4

Look at your quotation marks. Use the proper ones (ASCII quotes). Apart from that just use <br />