使用 Python 的正则表达式中的重音字符

Question

This is my code

# -*- coding: utf-8 -*-
import json
import re

with open("/Users/paul/Desktop/file.json") as json_file:
    file = json.load(json_file)
print file["desc"]

key="capacità"
result = re.findall("((?:[\S,]+\s+){0,3})"+key+"\s+((?:[\S,]+\s*){0,3})", file["desc"], re.IGNORECASE)
print result

This is the content of the file

{
    "desc": "Frigocongelatore, capacit\u00e0 di 215 litri, h 122 cm, classe A+"
}

My result is []

but what I want is result = "capacità"

Answer 1

You need to treat your string as an Unicode string, like this:

str = u"Frigocongelatore, capacit\u00e0 di 215 litri, h 122 cm, classe A+"

And as you can see if you print str.encode('utf-8') you'll get:

Frigocongelatore, capacità di 215 litri, h 122 cm, classe A+

The same way you can make your regex string an unicode or raw string with u or r respectively.

Answer 2

You can use this function to display different encodings.

The default encoding on your editor should be UTF-8. Check you settings with sys.getdefaultencoding() .

def find_context(word_, n_before, n_after, string_):
    # finds the word and n words before and after it
    import re
    b= '\w+\W+'  * n_before
    a=  '\W+\w+' * n_after
    pattern = '(' + b + word_ + a + ')'
    return re.search(pattern, string_).groups(1)[0]

s = "Frigocongelatore,  capacità di 215 litri, h 122 cm, classe A+"

# find 0 words before and 3 after the word capacità
print(find_context('capacità',0,3,s) )

capacità di 215 litri

print(find_context(' capacit\u00e0',0,3,s) )

 capacità di 215 litri