如何使用seq填充小数位数

Question

I can't figure out how to use seq to pad decimal places. Here is what I tried based on what i found online...

for U in $(seq -f "%0.2g" 0 0.1 1)

but it fails to work.

I am looking to get the output,

0.00
0.10
0.20
...

Answer 1

g in the file format notation removes trailing zeros. You want f :

seq -f "%0.2f" 0 0.1 1

resulting in

0.00
0.10
0.20
0.30
0.40
0.50
0.60
0.70
0.80
0.90
1.00

The relevant excerpts from the spec are these:

f , F

The floating-point number argument shall be written in decimal notation in the style [-] ddd . ddd , where the number of digits after the radix character (shown here as a decimal point) shall be equal to the precision specification.

e , E

The floating-point number argument shall be written in the style [-] d . ddd e± dd (the symbol '±' indicates either a <plus-sign> or minus-sign), where there is one digit before the radix character (shown here as a decimal point) and the number of digits after it is equal to the precision.

g , G

The floating-point number argument shall be written in style f or e (or in style F or E in the case of a G conversion specifier), with the precision specifying the number of significant digits. [...] Trailing zeros are removed from the result.