我在处理来自Django的404错误消息时遇到了麻烦。 它说“找不到与查询匹配的位置”

Question

So I am taking the One Month Python course online and I am having some issues. The thing is that my general expression (?P<pk>\\d+)/detail/$ does not seem to work hence the 404-message.

Here is my code: main urls.py

from django.conf.urls import patterns, include, url
from django.contrib import admin

urlpatterns = patterns ('',
    # blah blah
    # blah blah blah
    # Blaaaahhh

    url(r'^admin/', include(admin.site.urls)),
    (r'', include('core.urls')),
)

core/urls.py

from django.conf.urls import patterns, include, url
from django.contrib import admin
import core.views as coreviews

urlpatterns = patterns ('',

    url(r'^$', coreviews.LandingView.as_view()),
    url(r'location/$', coreviews.LocationListView.as_view()),
    url(r'location/(?P<pk>\d+)/detail/$', coreviews.LocationDetailView.as_view()),

)

Views:

from django.shortcuts import render
from django.views.generic.base import TemplateView
from django.views.generic.list import ListView
from django.views.generic.detail import DetailView
import core.models as coremodels
# Create your views here.

class LandingView(TemplateView):
    template_name = "base/index.html"


class LocationListView(ListView):
    model = coremodels.Location
    template_name = 'location/list.html'


class LocationDetailView(DetailView):
    model = coremodels.Location
    template_name = 'location/detail.html'
    context_object_name = 'location'

I have already created five locations using the Django admin site: https://gyazo.com/1db0b35fafdacb3d4991fbea3990ee61

Here is the actual error message:

Answer 1

The error message "No location found matching the query" suggests that the url pattern is correct, but there is no location with pk=1 in the database. You probably deleted it.

Try a different url eg /location/2/detail/ for a primary key that definitely exists.

You can find a primary key by doing something like Location.objects.first().id in the shell, or simply clicking on a location in the Django admin, and looking at the url.