如何在Python列表中每行返回每个唯一字符？

Question

I have a file (secret_message.txt) in the likes of:

Yap Cat Hat
Two Ants Like Two Ant Like Kids
Ants Like Cat Two

and I want to read each line individually and replace only one occurrence of:

Yap with Y
Cat with O
Hat with U
Two with T
Ants with A
Like with L
Kids with K

while ignoring repeated words, such that the output file reads:

YOU
TALK
ALOT

I plan to re-use the same secret code language for future messages, however, so I don't need to remake a new translation dictionary each time.

Any suggestions on how to do this most efficiently would be tremendously appreciated!

Below is what I have tried:

#!/usr/bin/env python

import os
import glob
import fileinput

filename = 'secret_message.txt'

with open(filename,'r') as f:
    f2 = f.read().split('\n')
    for line in f2:
        f3 = line.replace("Yap","Y",1)
        f3 = line.replace("Cat","O",1)
        f3 = line.replace("Hat","U",1)
        f3 = line.replace("Two","T",1)
        f3 = line.replace("Ants","A",1)
        f3 = line.replace("Like","L",1)
        f3 = line.replace("Kids","K",1)

with open('secret_answer.txt', 'w') as f:
    f.write(f3)

Answer 1

Maybe someone has a better solution, but if you build a list of potential keys before translating each line, then you can delete each key you use so that you ignore duplicates.

TRANSLATOR = {
    "Cat": "O",
    ...
}

def translate(line):
    keys = set(TRANSLATOR)
    secretStr = ""
    for word in line.split(" "):
        if word in keys:
            secretStr += TRANSLATOR[word]
            keys.remove(word)
    return secretStr