命令以获取xml文件的第二行并使用获取的名称重命名该文件

Question

I have an xml file names media.xml and it consist of:

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<table name="advisoryTable"/>
  <row>
      <field name="book">maths</field>
      <field name="book">science</field>
      <field name="book">eng</field>
  </row>
</table>

Is there any way where i can fetch "advisory table" name from xml file and rename my file from media.xml to advisory.xml

Thank you in advance

Answer 1

I'm hoping that your <table> element isn't actually self-closing, so your XML is valid. If so, you can extract the value of the name attribute using a tool such as xmllint :

xmllint --xpath 'string(/table/@name)' media.xml

The output of this command is advisoryTable . You could pipe the output to sed to remove the Table part:

xmllint --xpath 'string(/table/@name)' media.xml | sed 's/Table//'

If you're happy with the result, this could be used within a command substitution to rename your file:

mv media.xml "$(xmllint --xpath 'string(/table/@name)' media.xml | sed 's/Table//')"

I would be reluctant to encourage automatically renaming files in this way, as you run the risk of accidentally overwriting something. Perhaps it would be a better idea to copy the files instead, possibly using cp -n to avoid clobbering files that already exist with the same name.