如何将subprocess.call的结果打印到python脚本中的文件

Question

I have a python script where I call the JIRA API and getting something from JIRA, which I want to write out to file.

This command in cmd works fine

curl -D- -u username:password -X GET --data @file.json -H "Content-Type: application/json" http:URL >> output.json

However, when I try to do the same in Python, it is not writing to my file (goes right to my "something is wrong")

#Runs curl script to get component
def write():
    name = 'output.json'

try:
    file= open(name, 'w')
    file.write(subprocess.call('curl -D- -u username:password -X GET --data @file.json -H "Content-Type: application/json" http:URL'))
    file.close()

except:
    print('something is wrong')
    sys.exit(0)
write()

I also tried to just have it write the contents of a variable, below.

curler = (subprocess.call('curl -D- -u username:password -X GET --data @file.json -H "Content-Type: application/json" http:URL'))

def write():
    name = 'output.json'

try:
    file = open(name, 'w')
    file.write(curler)
    file.close()

except:
    print('something is wrong')
    sys.exit(0)
write()

I am using Windows 7 and Python 3

Answer 1

subprocess.call() takes a list of arguments and just returns the exit status of the process called. I think you are trying to redirect the standard output to a file:

curl = ['curl', '-D-', '-u', 'username:password', '-X', 'GET', '--data',
        '@file.json', '-H', 'Content-Type: application/json', 'http:URL']
with open('output.json', 'w') as file:
    status = subprocess.call(curl, stdout=file)

Answer 2

1- The reason you're getting an exception is because the way you pass arguments to subprocess. You should give subprocess a list of args and not a single string. Say you want to download google.com using curl:

subprocess.call(['curl', 'google.com'])

2- subprocess.call returns the exit code, not the output. To redirect the output to a file:

subprocess.call(['curl', 'google.com'], stdout=open('myFileName', 'w'))