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boost :: scoped_lock不起作用(对我来说)

[英]boost::scoped_lock not working (for me)

I am extending a code base,Have a look at the following code snippet taken out of a class. 我正在扩展代码库,请看以下从类中摘录的代码段。 I made it as simple as possible not to confuse you: 我尽可能地简化了您,以免混淆您:

std::queue< boost::shared_ptr<const Item> > _container;
boost::mutex _mutex;
//...
void foo(Item *item)
{
    boost::mutex::scoped_lock lock(_mutex);
    std::cout << "enter " << _container.size() << "  " << this << std::endl;
    boost::shared_ptr<const Item> instr(item);
    _container.push( instr );

    // we only need to signal when size turns from 0 --> 1
    if (_container.size() == 1)
    {
        std::cout << "SIGNALLING" << "  " << this << std::endl;
        signal();//pop the _container until empty
    }
    else
    {
        std::cout <<"NOT SIGNALLING " << _container.size() << "  " << this << std::endl;
    }
}

and I get this in stdout: 我在标准输出中得到这个:

enter 0  0xe919f0
enter 1  0xe919f0
NOT SIGNALLING 2  0xe919f0
enter 2  0xe919f0
NOT SIGNALLING 3  0xe919f0

....and so on. ....等等。 signal() is not called. signal()不被调用。 I printed this to show that we are operating on the same object. 我印this表明,我们正在同一个对象上进行操作。

How possibly/in what kind of scenarios can happen? 在哪种情况下可能/会发生什么? `'foo is entered twice initially (and messes with the rest of the logic) while it is being protected by a mutex! `'foo在被互斥锁保护的情况下最初被输入两次(并与其余逻辑混淆)!

I appreciate your solutions. 感谢您的解决方案。 Thank you 谢谢

How possibly/in what kind of scenarios can happen? 在哪种情况下可能/会发生什么? `'foo is entered twice initially (and messes with the rest of the logic) while it is being protected by a mutex! `'foo在被互斥锁保护的情况下最初被输入两次(并与其余逻辑混淆)!

This would happen when another thread accesses _container without synchronizing on the same mutex . 当另一个线程访问_container而不在同一个mutex _container进行同步时,就会发生这种情况。

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