[英]type mismatch: cannot convert from int to boolean in lotto program
I am trying to make a lotto java program.我正在尝试制作一个乐透 Java 程序。 I prompt the user to input their number and then generate a random number and if your number matches, you win but i'm getting the "type mismatch: cannot convert from int to boolean."
我提示用户输入他们的号码,然后生成一个随机数,如果你的号码匹配,你就赢了,但我得到了“类型不匹配:无法从 int 转换为布尔值”。 Here's what I have so far.
这是我到目前为止所拥有的。 Thank you for the help!
感谢您的帮助! Note i'm very new to java
请注意,我对 Java 很陌生
import java.util.Scanner;
import java.util.Random;
public class lottery
{
public static void main (String [] args)
{
Scanner input=new Scanner(System.in);
System.out.println("Please enter your number");
Random randomNumber=new Random();
System.out.println(" my random number is "+65);
System.out.println("lotto number is "+randomNumber.nextInt(10)+1);
if(65)
System.out.println("You win 20000");
else
Sytem.out.println("No winner");
if(56)
System.out.println("You win 10000");
else
System.out.println("No winner");
if(6||5)
System.out.println("You win 5000");
else
System.out.println("No winner");
}
}
You need to store the random number in a variable and compare it in the if statements:您需要将随机数存储在变量中并在 if 语句中进行比较:
import java.util.Scanner;
import java.util.Random;
public class lottery
{
public static void main (String [] args)
{
Scanner input=new Scanner(System.in);
System.out.println("Please enter your number");
Random randomNumber=new Random();
int rand = randomNumber.nextInt(10) + 1
System.out.println(" my random number is "+65);
System.out.println("lotto number is "+ rand);
if(rand == 65)
System.out.println("You win 20000");
else if(rand == 56)
System.out.println("You win 10000");
else if(rand == 6 || rand == 5)
System.out.println("You win 5000");
else
System.out.println("No winner");
}
}
Note: I fixed up your if statements a bit aswell.注意:我也稍微修正了你的 if 语句。 (You're still a winner if you get 56 right)
(如果你答对了 56,你仍然是赢家)
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