检查数据库中是否存在一行，如果不显示消息

Question

I can't manage to check if a row exists in database and if not display a message. The code is below. I need a little help.

<?php
    $result = mysqli_query($mysqli, "SELECT client_cv FROM formular_client WHERE id = '$id'"); 
   if (mysqli_num_rows($result) > 0){
       echo "<a href='../cv/" . $rows['client_cv'] . "' target='_blank' class='btn btn-lg btn-primary'><span class='glyphicon glyphicon-download-alt'></span> Descarca CV</a>";
   } else {
       echo "<a href='#' target='_blank' class='btn btn-lg btn-primary'><span  class='glyphicon glyphicon-download-alt'></span> Fara CV</a>";
   }
?>

Answer 1

if you want to show different links based on if client_cv has a value or not, try this

<?php
    $result = mysqli_query($mysqli, "SELECT client_cv FROM formular_client WHERE id = '$id'"); 
    if (mysqli_num_rows($result) > 0){
        $rows = mysqli_fetch_array($result);
        if (strlen($rows["client_cv"]) > 0){
            echo "<a href='../cv/" . $rows['client_cv'] . "' target='_blank' class='btn btn-lg btn-primary'><span class='glyphicon glyphicon-download-alt'></span> Descarca CV</a>";
        } else {
            echo "<a href='#' target='_blank' class='btn btn-lg btn-primary'><span  class='glyphicon glyphicon-download-alt'></span> Fara CV</a>";
        }
    } else {
        echo "No record found"
    }
?>