简体   繁体   English

url验证RegExp将电子邮件地址识别为url

[英]url validation RegExp recognize email address as url

I have to recognize url in some text. 我必须在某些文本中识别网址。 I use the following code ( this.value is the text): 我使用以下代码( this.value是文本):

if (new RegExp("([a-zA-Z0-9]+://)?([a-zA-Z0-9_]+:[a-zA-Z0-9_]+@)?([a-zA-Z0-9.-]+\\.[A-Za-z]{2,4})(:[0-9]+)?(/.*)?").test(this.value)) {
    alert("url inside");
}

The problem that is recognize also email address as url. 将电子邮件地址也识别为URL的问题。 How can I prevent it? 我该如何预防?

The expression /[a-zA-Z0-9_]/ is the same as /\\w/i . 表达式/[a-zA-Z0-9_]//\\w/i

The original RegExp matches the "domain.org" substring in a text like "text name@domain.org text mailto:name@domain-2.org text". 原始RegExp与“ domain.org”子字符串匹配,例如“ text name@domain.org text mailto:name@domain-2.org text”之类的文本。 To fix this add (?:^|[^@\\.\\w-]) at the beginning of the RegExp - a substring should be at the beginning of a line or should not begin with characters '@', '.', '-', '\\w'. 要解决此问题,请在RegExp的开头添加(?:^|[^@\\.\\w-]) -子字符串应位于行的开头,或者不应以字符'@','。'开始, '-','\\ w'。

To exclude "mailto:user@..." substrings the expression ([a-zA-Z0-9_]+:[a-zA-Z0-9_]+@)? 要排除“ mailto:user @ ...”子表达式的子字符串([a-zA-Z0-9_]+:[a-zA-Z0-9_]+@)? should be modified. 应该修改。 Because Javascript RegExp has no look-behind expressions the only way to exclude "mailto" is to use the look-ahead expression \\w(?!ailto:)\\w+: , but all substrings like "[a-zA-Z0-9_]ailto:...@..." will be excluded also. 因为Javascript RegExp没有后向表达式,所以排除“ mailto”的唯一方法是使用前向表达式\\w(?!ailto:)\\w+:但是所有子字符串都类似于“ [a-zA-Z0-9_ ] ailto:... @ ...”也将被排除。

To exclude from matches the substring "user.name" from a text like "text user.name@domain.org text" add the expression (?=$|[^@\\.\\w-]) at the ending of the RegExp - match a substring only if the end of line follows the substring or the following characters '@', '.', '-', '\\w' don't follow the substring. 要从匹配项中排除“ text user.name@domain.org text”之类的文本中的子字符串“ user.name”,请在RegExp的末尾添加表达式(?=$|[^@\\.\\w-]) -仅当行尾在子串之后或以下字符'@','。','-','\\ w'不跟随子串时,才匹配子串。

 var re = /(?:^|[^@\\.\\w-])([a-z0-9]+:\\/\\/)?(\\w(?!ailto:)\\w+:\\w+@)?([\\w.-]+\\.[az]{2,4})(:[0-9]+)?(\\/.*)?(?=$|[^@\\.\\w-])/im; //if (re.test(this.value)) { // alert("url inside"); //} var s1 = "text name@domain.org name.lastname@domain-2.org text mailto:user.name@domain-3.org text"; if (re.test(s1)) { alert("Failed: text without URL"); } var s2 = "text http://domain.org/ text"; if (!re.test(s2)) { alert("Failed: text with URL"); } alert("OK"); 

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM