在子进程中执行文件

Question

I have two programs in the same directory main and example, if I execute ./example file.txt it manages simple tasks with that file. Then my main program is

#include<stdio.h>
#include<stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>
int main (int argc, char* argv[]){
   pid_t const pid1 = fork();
   if(pid1==0){
     execv();
   }
   else{
     wait(NULL);
   }
 }

So I want to execute ./main file.txt and the child process should execute ./example file.txt with the same file that main has received in argv[1]. My question is how to use the execv parameters to accomplish this.
Sorry if I did not explained myself simple. Thank You

Answer 1

The easiest way to do this would be:

execl("./example", "example", argv[1], (char *)NULL);

Alternatively,

char *args[] = {
    "example",
    argv[1],
    NULL
};
execv("./example", args);