[英]Android dynamic variable for drawable resource
Hi I have a problem for my coding, how can I do this: 嗨,我的编码有问题,该怎么做:
BitmapFactory.decodeResource(getResources(), R.drawable."some string");
I'm using: 我正在使用:
getResources().getIdentifier(img, "drawable", context.getPackageName())
, getResources().getIdentifier(img, "drawable", context.getPackageName())
,
then it's showing: 然后显示:
error cannot resolve method decodeResource(int)
错误无法解决方法encodeResource(int)
Technically you can't do it that way, because "R.drawable.XXXXX" is an int that is generated at compile time. 从技术上讲,您不能那样做,因为“ R.drawable.XXXXX”是在编译时生成的int。 I would recommend making a custom enum that associates the int with the string and provides a method to return one given the other.
我建议创建一个自定义枚举,该枚举将int与字符串相关联,并提供一种返回给定另一个的方法。 For example:
例如:
public enum DrawableEnum {
STRING_ONE("some string", R.drawable.some_string),
STRING_TWO("another string", R.drawable.some_other_string),
STRING_THREE("third string", R.drawable.string_three);
private final String string;
private final int resId;
DrawableEnum(String string, int resId) {
this.string = string;
this.resId = resId;
}
int getResId() {
return resId;
}
String getString() {
return string;
}
int getResIdFromString(String string) {
for(DrawableEnum item : DrawableEnum.values()) {
if(item.getString().equals(string)) {
return item.getResId();
}
}
return -1;
}
}
Then call it like this: 然后这样称呼它:
int resId = DrawableEnum.getResIdFromString("some string");
BitmapFactory.decodeResource(getResources(), resId);
You will be able to get resource id with the following code: 您将可以使用以下代码获取资源ID:
int resId = getResources().getIdentifier("some_string", "drawable", getPackageName());
BitmapFactory.decodeResource(getResources(), resId);
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