[英]How can I pass a variable value from JavaScript to PHP
I've tried this and I do not know if it is the right way: 我已经尝试过了,但不知道这是否正确:
HTML Code: HTML代码:
<div class="container-fluid">
<form class="form-inline">
<div class="form-group">
<label>Choose Records Per Page:</label>
<select class="form-control input-sm num_rec_per_page">
<option>5</option>
<option>10</option>
<option>50</option>
<option>100</option>
<option>150</option>
<option>200</option>
</select>
</div>
</form>
</div>
JAVASCRIPT Code: JAVASCRIPT代码:
<script>
$(document).ready(function(){
$("select.num_rec_per_page").change(function(){
$(".num_rec_per_page option:selected").val();
window.location="?num_rec_per_page=" + num_rec_per_page;
});
});
</script>
PHP Code PHP代码
$num_rec_per_page=$_GET['num_re_per_page'];
So this code, when the variable changes, a refresh is made to the webpage, but I do not want that, can you help me?? 因此,当变量更改时,此代码会刷新网页,但我不希望这样做,您能帮我吗?
You didn't specify your exact end goal with getting the JS variable to PHP, but I assume it's to get the value of the select so you can change the number of records displayed per page (inferring from variable names). 您没有通过将JS变量转换为PHP来指定确切的最终目标,但我认为这是要获取select的值,因此您可以更改每页显示的记录数(从变量名推断)。
If you want to avoid a page refresh, you could do this via AJAX and pull in additional records to display using JavaScript. 如果要避免页面刷新,可以通过AJAX进行操作,并提取其他记录以使用JavaScript进行显示。 If you assign a new value to
window.location
, it will refresh the page. 如果将新值分配给
window.location
,它将刷新页面。
You would want something like 你会想要像
$(selector).load('/get_results.php?num_rec_per_page=' + num_rec_per_page);
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