如何在 Linux 中删除早于特定日期的文件？

Question

I used the below command to delete files older than a year.

  find /path/* -mtime +365 -exec rm -rf {} \;

But now I want to delete all files whose modified time is older than 01 Jan 2014. How do I do this in Linux?

Answer 1

这对我有用：

find /path ! -newermt "YYYY-MM-DD HH:MM:SS" | xargs rm -rf

Answer 2

You can touch your timestamp as a file and use that as a reference point:

eg for 01-Jan-2014:

touch -t 201401010000 /tmp/2014-Jan-01-0000

find /path -type f ! -newer /tmp/2014-Jan-01-0000 | xargs rm -rf 

this works because find has a -newer switch that we're using.

From man find :

-newer file
       File  was  modified  more  recently than file.  If file is a symbolic
       link and the -H option or the -L option is in effect, the modification time of the 
       file it points to is always used.

Answer 3

This other answer pollutes the file system and find itself offers a "delete" option. So, we don't have to pipe the results to xargs and then issue an rm.

This answer is more efficient:

find /path -type f -not -newermt "YYYY-MM-DD HH:MI:SS" -delete

Answer 4

find ~ -type f ! -atime 4|xargs ls -lrt

这将列出访问时间超过 4 天的文件，从主目录搜索。