通过将其指针传递给函数来输出矩阵的值

Question

I am trying to send a pointer of a matrix to function for printing the values. However, my following code prints some long numbers so I assumed it prints the addresses instead! How can I print the value of the matrix after passing the pointer of it?

#include <stdio.h>
#include <string.h>
#include <math.h>

void printing(int *edge);
void main(){

int N=3;
int i,j;

int *edge[N]; 
for (i = 0; i < N; i++){
    *(edge+i) = (int *)malloc(N * sizeof(int));
}

srand(0);
for(i = 0; i < N; i++){
    for(j = 0; j < N; j++){
        if(i == j)
            *(*(edge+i)+j) = 0;
        else
            *(*(edge+i)+j) = 1; //rand() % 10;  
    }
}

printing(edge); // Pass the pointer of the matrix


}


void printing(int *edge){

int i,j; 
int N= 3;   
for( i = 0; i < N; i++){
   for(j = 0; j < N; j++){
       printf("%d \t", ((edge+i)+j)); // I think I have to do something in this line.
   }
       printf("\n");
}

}

Answer 1

The parameter type of printing is incorrect. It should be int *edge[] . Then when you print, use *(*(edge+i)+j) , or better yet edge[i][j] .

The result:

void printing(int *edge[]){
    int i,j; 
    int N = 3;   
    for( i = 0; i < N; i++){
       for(j = 0; j < N; j++){
           printf("%d \t", edge[i][j]);
       }
       printf("\n");
    }
}

Also, be sure to #include <stdlib.h> , as it's needed for malloc and srand .