如何使用PHP查询MS SQL Server而不列出列名？

Question

I am using PHP to query a Microsoft SQL Server and returning the result set. 我正在使用PHP查询Microsoft SQL Server并返回结果集。 My issue is the PHP code returns the result set that I want, however it is only a partial result set. 我的问题是PHP代码返回我想要的结果集，但是它只是部分结果集。

The full table has 6 columns of data for this example 对于此示例，完整表具有6列数据

Below is the code snippet of the table design in the Database in an HTML Snippet: 以下是HTML代码段中数据库中表设计的代码段：

 <!DOCTYPE html> <html> <body> <table border="1" style="width:100%"> <tr> <td>COL1</td> <td>COL2</td> <td>COL3</td> <td>COL4</td> <td>COL5</td> <td>COL6</td> </tr> <tr> <td>rowdata</td> <td>rowdata</td> <td>rowdata</td> <td>rowdata</td> <td>rowdata</td> <td>rowdata</td> </tr> <tr> <td>rowdata</td> <td>rowdata</td> <td>rowdata</td> <td>John</td> <td>rowdata</td> <td>rowdata</td> </tr> </table> </body> </html>

Below is the PHP Script used to query the SQL Server: 以下是用于查询SQL Server的PHP脚本：

<?php    

$serverName = "sqlserver";   
$uid = "username";     
$pwd = "password";    
$databaseName = "databasename";   

$connectionInfo = array( "UID"=>$uid,                              
                         "PWD"=>$pwd,                              
                         "Database"=>$databaseName);   


/* Connect using SQL Server Authentication. */    
$conn = sqlsrv_connect( $serverName, $connectionInfo); 

$tsql = "SELECT * FROM TABLE " ;  


/* Execute the query. */    

$stmt = sqlsrv_query( $conn, $tsql);  


if ( $stmt )    
{    
     echo "Statement executed.<br>\n";    
}     
else     
{    
     echo "Error in statement execution.\n";    
     die( print_r( sqlsrv_errors(), true));    
}    


    //Working Query
/* Iterate through the result set printing a row of data upon each iteration. */

  while($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)){
 foreach ($row as $column=>$value)


   {
      echo 
       $column.": " .$value."<br />";

   }
   echo '<hr />';

}





/* Free statement and connection resources. */    
sqlsrv_free_stmt( $stmt);    
sqlsrv_close( $conn);    

?>

This is the issue only 4 columns are returned and 1 row of data for those 4 columns 这对于那些4列的问题，只返回4列和1行数据的

Example of what is returned in PHP Console: PHP控制台返回的示例：

Statement executed.<br>
COL1: rowdata<br />COL2: rowdata<br />COL3: rowdata<br />COL4: rowdata<br />

If you cannot already tell, I am attempting to display the full result set of the query without listing the columns in PHP. 如果您还不能确定，我将尝试显示查询的完整结果集，而不在PHP中列出各列。

IE IE浏览器

echo $row[1];
echo $row[2];
echo $row[3];

etc. 等等

--------------------------------------------------- UPDATE ------------------------------------------------------------ -------------------------------------------------- - 更新 ------------------------------------------------ ------------

I have found there is an issue with the DATETIME Columns in the SQL Server. 我发现SQL Server中的DATETIME列存在问题。 When I CAST() the columns in the SQL Query being passed in the PHP code, it returned the full Result Set. 当我CAST（）在PHP代码中传递SQL查询中的列时，它返回了完整的结果集。 This is a work around, however I would like to retain the DATETIME format and just pass a query through instead of Casting it. 这是一种变通方法，但是我想保留DATETIME格式，只是通过查询而不是强制转换。

Thoughts? 有什么想法吗？

UPDATED CODE: 更新的代码：

/* Connect using SQL Server Authentication. */    
$conn = sqlsrv_connect( $serverName, $connectionInfo); 

$tsql = "SELECT
COL1,
COL2,
COL3,
CAST(COL4 AS VARCHAR) 'COL4'
COL5,
COL6  
FROM TABLE " ;

Example of what is returned in PHP Console: PHP控制台返回的示例：

  Statement executed.<br>
    COL1: rowdata<br />COL2: rowdata<br />COL3: rowdata<br />COL4: rowdata<br />COL5: rowdata<br />COL6: rowdata<br />
COL1: rowdata<br />COL2: rowdata<br />COL3: rowdata<br />COL4: rowdata<br />COL5: rowdata<br />COL6: rowdata<br />

As you can see it returns the entire result set of the table. 如您所见，它返回表的整个结果集。

Answer 1

Your code is trying to read rows as an associate array. 您的代码试图将行作为关联数组读取。 Try using sqlsrv_fetch_assoc instead of sqlsrv_fetch_array as you're doing now. 现在，请尝试使用sqlsrv_fetch_assoc而不是sqlsrv_fetch_array 。

//replace the function call in the line below!
while($row = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)){
 foreach ($row as $column=>$value)


   {
      echo 
       $column.": " .$value."<br />";

   }
   echo '<hr />';

}

如何使用PHP查询MS SQL Server而不列出列名？

问题描述

1 个解决方案

解决方案1
0 2015-10-14 19:05:53

如何使用PHP查询MS SQL Server而不列出列名？

问题描述

1 个解决方案

解决方案1 0 2015-10-14 19:05:53

解决方案1
0 2015-10-14 19:05:53