PL / SQL Developer中的Oracle SQL上的两个表和多个条件之间的完全外部联接不起作用

Question

I need help with a Join NOT WORKING in PL/SQL Developer under Oracle SQL. I have a table VALUES which have multiple columns. Its structure is:

CYCLE|PERIOD|FEE|CITY|SERVICE_NAME|CLIENT_TYPE|VALUE

what I want to do is to add another column new to VALUE, and name it as PREVIOUS_VALUE. It will contain the field VALUE for the row which have the same values in CYCLE, FEE, CITY, SERVICE_NAME and CLIENT_TYPE, the only difference is that it belong to a PERIOD' = PERIOD - 1. In other words, I want to add the value of the previuos period next to the VALUE in the table.

My strategy was the following: 1) Create a view VV_VIEW which contains the same fields as the table VALUES, created as following:

CREATE OR REPLACE VIEW VV_VIEW as SELECT CYCLE, PERIOD,
PREVIOUS_PERIOD(PERIOD) AS PREV_PERIOD, FEE, CITY, SERVICE_NAME, 
CLIENT_TYPE, VALUE FROM VALUES.

2) Do a FULL OUTER JOIN on VV_VIEW AND VALUES selectin all the columns from VV_VIEW and ADDING IT the column VALUE from the table VALUES with the condition that VALUES.PERIOD = VV_VIEW.PREVIOUS_PERIOD and also VALUES.CYCLE = VV_VIEW.CYCLE, VALUES.FEE = VV_VIEW.FEE, VALUES.CITY = VV_VIEW.CITY, etc. The exact query looks like this:

CREATE OR REPLACE VIEW FINAL_VIEW AS SELECT VV_VIEW.CYCLE, 
VV_VIEW.PERIOD, VV_VIEW.PREV_PERIOD, VV_VIEW.FEE, VV_VIEW.CITY, 
VV_VIEW.SERVICE_NAME, VV_VIEW.CLIENT_TYPE, VALUES.VALUE AS PREV_VALUE
FROM VV_VIEW FULL OUTER JOIN VALUES 
ON VV_VIEW.PREV_PERIOD = VALUES.PERIOD AND VV_VIEW.FEE = VALUES.FEE AND
VV_VIEW.CITY = VALUES.CITY AND VV_VIEW.SERVICE_NAME = 
VALUES.SERVICE_NAME AND
VV_VIEW.CLIENT_TYPE = VALUES.CLIENT_TYPE;

So that the VALUE from the previous period will appear next to the actual VALUE in the new view.

The problem is, FULL OUTER JOIN does not seem to work. When I use RIGHT OUTER JOIN I get the values in the PREV_VALUE COLUMN, but the other columns are NULL. If I use LEFT OUTER JOIN I get all the columns with their respective valur, except for PREV_VALUE, which remains NULL. With the FULL OUTER JOIN I get results similars to those of using LEFT JOIN.

Could you please tell me what am I doing wrong?

What I want, in simple terms is something like this:

** TABLE VALUES = ORIGINAL TABLE

CYCLE|PERIOD|FEE|CITY|SERVICE_NAME|CLIENT_TYPE|VALUE

03 |201404|0.5|CTTA|TELEPHONE_SM| PREMIUM   | 3000

03 |201405|0.7|CMFE|TELEPHONE_MM| PREMIUM   | 2000

04 |201312|0.2|CTDA|TELEPHONE_SM| STANDARD  | 500

.....

03 |201403|0.5|CTTA|TELEPHONE_SM| PREMIUM   | 9000

03 |201404|0.7|CMFE|TELEPHONE_MM| PREMIUM   | 8000

.....

03 |201402|0.5|CTTA|TELEPHONE_SM| PREMIUM   | 1000

03 |201403|0.7|CMFE|TELEPHONE_MM| PREMIUM   | 2000

.....

and get this new view:

***FINAL_VIEW

CYCLE|PERIOD|PREV_PERIOD|FEE|CITY|SERVICE_NAME|CLIENT_TYPE|VALUE | PREV_VALUE

03 |201404  | 201403    |0.5|CTTA|TELEPHONE_SM| PREMIUM   | 3000 | 9000

03 |201405  | 201404    |0.7|CMFE|TELEPHONE_MM| PREMIUM   | 2000 | 8000

04 |201312  | 201403    |0.2|CTDA|TELEPHONE_SM| STANDARD  | 500  | ....

.....

03 |201403  | 201402    |0.5|CTTA|TELEPHONE_SM| PREMIUM   | 9000 | 1000

03 |201404  | 201403    |0.7|CMFE|TELEPHONE_MM| PREMIUM   | 8000 | 2000 

.....

03 |201402  | 201401    |0.5|CTTA|TELEPHONE_SM| PREMIUM   | 1000 | .....
..............

I hope you get hat I'm trying to do. If you have an alternative approach to accomplish this, I would really like to hear from it. Thanks in advance.

EDIT: Fixed a typo in the query.

Answer 1

Try below, you should get your expected results, I have used "0" (third parameter in lag function ) when previous value is not present you can use null or any other value

select 
cycle,
period,
fee,
city,
service_name,
client_type,
value,
lag(period,1,0) over (partition by cycle,fee,city,service_name,client_type order by period) as prev_period,
lag(value,1,0) over (partition by cycle,fee,city,service_name,client_type order by period) as prev_value
from table1
order by cycle,fee,city,service_name,client_type,period;

2nd Query to verify for previous 3 values

select 
cycle,
period,
fee,
city,
service_name,
client_type,
value,
row_number() over (partition by cycle,fee,city,service_name,client_type order by period) as rn,
lag(value,1,0) over (partition by cycle,fee,city,service_name,client_type order by period) as prev_value1,
lag(value,2,0) over (partition by cycle,fee,city,service_name,client_type order by period) as prev_value2,
lag(value,3,0) over (partition by cycle,fee,city,service_name,client_type order by period) as prev_value3
from table1
order by cycle,fee,city,service_name,client_type,period;