如何将输出从 grep 管道传输到 cp？

Question

I have a working grep command that selects files meeting a certain condition. How can I take the selected files from the grep command and pipe it into a cp command?

The following attempts have failed on the cp end:

grep -r "TWL" --exclude=*.csv* | cp ~/data/lidar/tmp-ajp2/

cp: missing destination file operand after '/home/ubuntu/data/lidar/tmp-ajp2/' Try 'cp --help' for more information.

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cp `grep -r "TWL" --exclude=*.csv*` ~/data/lidar/tmp-ajp2/

cp: invalid option -- '7'

Answer 1

grep -l -r "TWL" --exclude=*.csv* | xargs cp -t ~/data/lidar/tmp-ajp2/

Explanation:

• grep -l option to output file names only
• xargs to convert file list from the standard input to command line arguments
• cp -t option to specify target directory (and avoid using placeholders)

Answer 2

you need xargs with the placeholder option:

grep -r "TWL" --exclude=*.csv* | xargs -I '{}' cp '{}' ~/data/lidar/tmp-ajp2/

normally if you use xargs , it will put the output after the command, with the placeholder ( '{}' in this case), you can choose the location where it is inserted, even multiple times.

Answer 3

在搜索具有特定日期的文件时，这对我有用：

 ls | grep '2018-08-22' | xargs -I '{}' cp '{}' ~/data/lidar/tmp-ajp2/

Answer 4

To copy files to grep found directories, use -printf to output directories and -i to place the command argument from xarg (after pipe)

find ./ -name 'filename.*' -print '%h\n' | xargs -i cp copyFile.txt {}

this copies copyFile.txt to all directories (in ./) containing "filename"

Answer 5

grep -rl '/directory/' -e 'pattern' | xargs cp -t /directory