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将表A和表B之间的不同行插入表B

[英]Insert different rows between Table A and Table B into Table B

I have two exactly identical tables. 我有两个完全相同的表。 Table A has eg 100 rows, Table B has 60 rows. 表A有例如100行,表B有60行。 Now I want to insert the "missing" rows from Table A into Table B. To find the different rows I would use: 现在,我想将表A中的“缺失”行插入表B中。要找到不同的行,我将使用:

select * from tableA where language = 4
union
select * from tableB where language = 4

How do I use this code correctly with the "Insert into" statement? 如何在“插入到”语句中正确使用此代码? My idea: 我的点子:

Insert into tableB
(Select * from tableA where language = 4
union
select * from tableB where language = 4)

Best regards 最好的祝福

UNION may be an option but it would cause duplications. UNION可能是一个选项,但会导致重复。 I would prefer MINUS operation. 我更喜欢减号操作。

insert into tableB (
select * from tableA where language=4
MINUS
select * from tableB where language=4)
Insert into tableB
(Select * from tableA where language = 4
EXCEPT
select * from tableB where language = 4)

Perhaps EXCEPT ALL should be used, treats duplicates differently. 也许应该使用EXCEPT ALL ,以不同的方式对待重复项。

Outer Join 外连接

INSERT INTO TableB (Column1,Column2) 
  SELECT DISTINCT
    a.Column1 ,
    a.Column2 ... more column
  FROM    TableA AS a
    LEFT OUTER JOIN TableB AS b ON b.Column1 = a.Column1 
                                          AND b.Column2 = a.Column2 
    WHERE b.Colum2 IS NULL AND b.Colum1 IS NULL ; 

Not Exists 不存在

INSERT INTO TableB (Column1,Column2) 
SELECT  a.Column1 ,
    a.Column2...
FROM    Table1 AS a
WHERE   NOT EXISTS ( SELECT *
                 FROM   Table2 AS b
                 WHERE  b.Column1 = a.Column1 
                        AND b.Column2= a.Column2);

Except 除了

INSERT INTO TableB (Column1,Column2) 
SELECT  Column1,
    Column2
FROM    TaBLE1
EXCEPT
SELECT  Column1,
    Column2
FROM    #TaBLE2;

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