将Javascript变量传递到JSON请求中
[英]Passing a Javascript Variable into a JSON request
问题描述
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学习者驾驶员警报！
I'm trying to transfer the search field content from the form below named variable "name" & input it into the flickr API JSON Request tags field (line 40 below). 我正在尝试从命名变量“ name”下面的表单中传输搜索字段内容，并将其输入到flickr API JSON Request标签字段（下面的第40行）中。 I've tried all sorts of ways of declaring the variable & can't seem to find what I'm looking for on the web. 我尝试了各种声明变量的方法，但似乎找不到我在网上寻找的内容。 I'm guessing that its me not knowing exactly what I'm searching for. 我猜想那是我不完全知道我在寻找什么。
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>jQuery.getJSON demo</title>
<style>
img {
height: 100px;
float: left;
}
</style>
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
<form id="search">
<p><input id="search-name" type="text" placeholder="Type Region Here"></p>
<p><input id="search-submit" type="submit" value="Search For Region"></p>
</form>
<div id="images"></div>
<script>
var name;
$("#search").submit(function(event){
event.preventDefault();
var name = $("#search-name").val();
console.log("Search Term Was: "+name);
return false;
});
$("#search").submit(function(event) {
(function() {
var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON( flickerAPI, {
tags: name,
tagmode: "any",
format: "json"
})
.done(function( data ) {
$.each( data.items, function( i, item ) {
$( "<img>" ).attr( "src", item.media.m ).appendTo( "#images" );
if ( i === 0 ) {
return false;
}
});
});
})();
});
</script>
</body>
</html>
Would anyone be so kind to help / put me in the right direction? 有人会这么乐于帮助我/朝正确的方向发展吗？
2 个解决方案
解决方案1
1 2015-10-15 08:37:27
You do not need 2 event listeners for this.
var name = $("#search-name").val();will create local scope fornamehence you won't find value in globalname.name创建本地范围，因此您将无法在全局name找到值。
Try it this way: 尝试这种方式：
$("#search").submit(function(event) { event.preventDefault(); var name = $("#search-name").val(); var flickerAPI = "http://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?"; $.getJSON(flickerAPI, { tags: name, tagmode: "any", format: "json" }) .done(function(data) { $.each(data.items, function(i, item) { $("<img>").attr("src", item.media.m).appendTo("#images"); if (i === 0) { return false; } }); }); });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <!doctype html> <html lang="en"> <head> <meta charset="utf-8"> <title>jQuery.getJSON demo</title> <style> img { height: 100px; float: left; } </style> </head> <body> <form id="search"> <p> <input id="search-name" type="text" placeholder="Type Region Here"> </p> <p> <input id="search-submit" type="submit" value="Search For Region"> </p> </form> <div id="images"></div> </body> </html>
解决方案2
1 2015-10-15 08:50:44
Running the jQuery as so seems to work for me. 这样运行jQuery似乎对我有用。 You could test it out but also note that i changed the reference to flicker to be loaded as secure script: 您可以对其进行测试，但也请注意，我将对闪烁的引用更改为作为安全脚本加载：
var name;
$("#search").submit(function(event){
event.preventDefault();
name = $("#search-name").val();
alert("Search Term Was: "+name);
var flickerAPI = "https://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON( flickerAPI, {
tags: name,
tagmode: "any",
format: "json"
})
.done(function( data ) {
alert('done');
$.each( data.items, function( i, item ) {
$( "<img>" ).attr( "src", item.media.m ).appendTo( "#images" );
if ( i === 0 ) {
return false;
}
});
})
.fail(function() {alert('fail')});
});
JS Fiddle: https://jsfiddle.net/vsw3r31k/ JS小提琴： https : //jsfiddle.net/vsw3r31k/
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