返回函数值javascript递归

Question

Using recursion return value of this function. Only one parameter is allowed in function. Also global variables outside of function are not allowed.

Answer 1

using your code with two parameters, assuming it's correct, cheat like this

function f(x) {
    function inner(n, i) { 
        if (n>0) { 
            return (( n / (1 + i)) + inner(n-1, i+1) ); 
        }
        else {
            return 0;
        } 
    }
    return inner(x);
}

or you can of course do this

function test(o) {
    if (typeof o == 'number') {
        o = { i: 0, n: o };
    }
    if (o.n > 0) {
        return ((o.n / (1 + o.i)) + test({ n: o.n - 1, i: o.i + 1 }));
    } else {
        return 0;
    }
}