在命令提示符下无输出

Question

My program, which is for generating an acceptable password, is not displaying any output aside from input prompt and it lets me input the password but the program immediately ends. I get no errors on my end or warnings on my debugger. Was wondering if someone could give me some input.

#include "stdafx.h"
#include <stdio.h>
#include <ctype.h>
#include <string.h>


int main()
{
    char password[15] = {'\0'};
    char search[15] = { '\0' };
    int a, b, c, d, e;
    char punct[] = { '!','@','#','$','%','^','&','*','?','_', '\0' };

    printf("Enter your test password: \n");
    fgets(password, 15, stdin );

    a = strnlen(password, 15);//judges length of search between the numbers 2 and 15
    b = strncmp(password, punct, 10);
    c = isalpha(strnlen(password,15));
    d = isdigit(strnlen(password, 15));
    e = a + b + c + d;

    if (a < 2 || a>15) {

        printf("Must have exactly 2-15 characters.\n");

        if (strncmp(password, punct, 10) == false) {//must have one of the characters included in password
            printf("Must have character punctutation\n");
        }
        if (isdigit(strnlen(password, 15)) == false) {
            printf("Must consist of at least one number 0-9.\n");
        }
        if (isalpha(strnlen(password, 15)) == false) {
            printf("Must consist of at least one letter a-z\n");
        }
        else {
            printf("You have inputted a legal password!\n");
        }

    }
        return 0;
    }

Answer 1

You are not getting an output because strnlen(password, 15) is between 2 and 15 , use an else part:

if (a < 2 || a > 15) {
   ...
} else {
   /* your output here */
}

On the other hand:

if (isdigit(strnlen(password, 15)) == false) {

is a nonsense, isdigit checks if a character is a decimal digit, but you are passing a size_t instead of a char , same for isalpha .