如何计算Python中两个嵌套列表之间的差异？

Question

If I had the two following lists with tuples in the form of (x,y):

 [(a,1),(b,2),(c,7),(d,1)]
 [(a,3),(b,2),(c,7),(d,8)]

I want to count the number of differences with respect to 'y' value for corresponding 'x' values. In the above case, the answer is 2

(a, 1 ) doesn't match with (a, 3 )

(d, 1 ) doesn't match with (d, 8 )

EDIT: This is not a duplicate, the position of the elements matter. I want to check if element 1 in list 1 is same as element 1 in list 2 and so on.

Answer 1

您可以使用zip函数和sum函数中的生成器表达式：

count=sum(i!=j for i,j in zip(list1,list2))

Answer 2

Another method is

x = [("a", 1) ,("b", 2), ("c", 7), ("d", 1)]
y = [("a", 3), ("b", 2), ("c", 7), ("d", 8)]
count = len(set(x).intersection(y))