[英]Returning out of void method from nested method
If I have a void method I can do something like this to break out of it early 如果我有一个无效的方法,我可以做这样的事情早日摆脱它
public void CheckIntNotLessThanZero(int value)
{
if (int < 0)
{
return;
}
Console.WriteLine("Not less than zero!")
}
However I run that exact same check several times and so I want to put it into its own method so I don't repeat code: 但是我多次运行完全相同的检查,因此我想将其放入自己的方法中,所以我不重复代码:
public void CheckIntNotLessThanZero(int value)
{
return CheckIntValue(value);
Console.WriteLine("Not less than zero!")
}
public void CheckIntValue(int value)
{
if (value < 0)
{
return;
}
}
That's a basic example but is there a way to do this? 那是一个基本的例子,但是有办法吗?
Turn your Check...
methods to return bool
value, and check it after every call: 打开您的
Check...
方法以返回bool
值,并在每次调用后对其进行检查:
public bool CheckIntValue(int value)
{
return value < 0;
}
public void CheckIntNotLessThanZero(int value)
{
if (CheckIntValue(value))
return;
Console.WriteLine("Not less than zero!")
}
Note, that you could throw exceptions in Check...
methods, but you must not . 请注意,您可以在
Check...
方法中引发异常,但一定不能 。 To manage execution flow using exceptions is a bad practice. 使用异常来管理执行流程是一种不好的做法。
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