我怎样才能选择div中的最后一个span元素？ 它不应该选择div中是否只有一个跨度

Question

I have HTML like this

 $('.elementContainers').find('.labelText:last:not(".labelText:first")').css('margin-left','150px'); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.2.3/jquery.min.js"></script> <div class="elementContainers"> <span class="labelText mandatory" >First Name</span> <span class="spacing"></span> <input type="text" class="customInput" id="firstName" name="firstName" value="" pattern="[A-Za-z]{2,}" required/> <span class="labelText" >Last Name</span> <span class="spacing"></span> <input type="text" class="customInput" id="lastName" value="" name="lastName" pattern="[A-Za-z]{1,}" required/> </div> <div class="elementContainers"> <span class="labelText mandatory" >Gender</span> <span class="spacing"></span> <input type="radio" name="gender" >Male <input type="radio" name="gender" >Female </div> 

I want to select last labelText in every elementContainer

$('.elementContainers').find('.labelText:last')

This gives me exactly what i need,but i need to check that first and last should not be the same( elementContainer should contain two elements )

How can i check that with :not selector or any other selector.

I have tried something like this

$('.elementContainers').find('.labelText:last:not(".labelText:first")')

But its not working,its returning no elements.

Thanks :)

Answer 1

If you want to select the last span in a div, but only where there is more than one span in the div, then the following selector should work.

$('div').find('span:gt(0):last').addClass('selected');

It's finding any span's at an index > 0 ( https://api.jquery.com/gt-selector/ ), and then getting the last of those.

http://jsfiddle.net/daveSalomon/vnorunwm/

Your code could look something like this....

$('.elementContainers').find('.labelText:gt(0):last').css('margin-left','150px');

http://jsfiddle.net/daveSalomon/qoebk8j9/

Answer 2

If there is as option to change html I will make a try using label instead of span and without using jquery at all only with css:

 .elementContainers label:last-of-type:not(:first-child) { margin-left: 150px; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.2.3/jquery.min.js"></script> <div class="elementContainers"> <label class="labelText mandatory">First Name</label> <span class="spacing"></span> <input type="text" class="customInput" id="firstName" name="firstName" value="" pattern="[A-Za-z]{2,}" required/> <label class="labelText">Last Name</label> <span class="spacing"></span> <input type="text" class="customInput" id="lastName" value="" name="lastName" pattern="[A-Za-z]{1,}" required/> </div> <div class="elementContainers"> <label class="labelText mandatory">Gender</label> <span class="spacing"></span> <input type="radio" name="gender">Male <input type="radio" name="gender">Female </div> 

References

:last-of-type

Answer 3

You can use .filter() method and you can return that element which have .labelText length of 2:

 $('.elementContainers').filter(function(){ return $(this).find('.labelText').length == 2 }).find('.labelText').last().css('margin-left','150px'); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="elementContainers"> <span class="labelText mandatory" >First Name</span> <span class="spacing"></span> <input type="text" class="customInput" id="firstName" name="firstName" value="" pattern="[A-Za-z]{2,}" required/> <span class="labelText" >Last Name</span> <span class="spacing"></span> <input type="text" class="customInput" id="lastName" value="" name="lastName" pattern="[A-Za-z]{1,}" required/> </div> <div class="elementContainers"> <span class="labelText mandatory" >Gender</span> <span class="spacing"></span> <input type="radio" name="gender" >Male <input type="radio" name="gender" >Female </div> 

Answer 4

Check that the length of your collection is greater than 1 before proceeding...

if ($('.elementContainers').find('.labelText').length > 1) {
    $('.elementContainers').find('.labelText:last').css('margin-left','150px');
}

Answer 5

尝试这个

$('.elementContainers .labelText:last').not($('.elementContainers .labelText:first'))

Answer 6

Try this

 $('.elementContainers').each(function(){ if($(this).find('.labelText').length > 1 ){ $(this).find('.labelText:last').css('margin-left','150px'); } }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.2.3/jquery.min.js"></script> <div class="elementContainers"> <span class="labelText mandatory" >First Name</span> <span class="spacing"></span> <input type="text" class="customInput" id="firstName" name="firstName" value="" pattern="[A-Za-z]{2,}" required/> <span class="labelText" >Last Name</span> <span class="spacing"></span> <input type="text" class="customInput" id="lastName" value="" name="lastName" pattern="[A-Za-z]{1,}" required/> </div> <div class="elementContainers"> <span class="labelText mandatory" >Gender</span> <span class="spacing"></span> <input type="radio" name="gender" >Male <input type="radio" name="gender" >Female </div> 

Answer 7

you have to first check the length of span element inside div if length is greater then 1 then get the last span inside div ,

you can get the length using

var span_lenght = $( ".elementContainers span" ).length;
if(span_lenght>1)
{
  // write your code here
}