Oracle SQL 子查询

Question

Display employee last_name , salary and job who work either in IT or MARKETING department and earn more than the worst paid person in the ACCOUNTING department. Sort the output by the last name alphabetically.

My answer:

select 
    last_name, salary, job_id 
from 
    employees 
where 
    salary > (select min(salary) 
              from employees 
              where department_id = (select department id 
                                     from departments 
                                     where department_name like'IT' 
                                        or like 'Marketing'));

Answer 1

Not exactly sure what you want, but it sounds something like this. Add other columns in select query as you want.

http://sqlfiddle.com/#!9/cfb31c/5/0

select e.last_name,e.salary,e.department_id from
employee e inner join department d
on e.department_id=d.department_id
where d.department_name in ('IT','MARKETING')
and e.salary > (select min(e1.salary) from employee e1
                inner join department d1
                where e1.department_id=d1.department_id
                and d1.department_name = 'ACCOUNTING')
order by e.last_name

Update

Same statement, reformatted.
Also removed inner keyword and fixed on clause, so SQL is vendor neutral, ie works on MySQL, MS SQL, Oracle, PostgreSQL, ...

select e.last_name, e.salary, e.department_id
  from employee e
  join department d on d.department_id = e.department_id
 where d.department_name in ('IT','MARKETING')
   and e.salary > ( select min(e1.salary)
                      from employee e1
                      join department d1 on d1.department_id = e1.department_id
                     where d1.department_name = 'ACCOUNTING' )
 order by e.last_name