第二次尝试后Java循环停止工作

Question

I am trying to make a console game (like Oregon trails) and I had a problem with the loop but was solved later.

**this is just part of the code of the whole game.

Now the problem is, the loop doesn't work after the second try; here is the code:

 int o1, o2, o3, o4, o5, o6, o7, o8, o9;
boolean thugloop = false;
 System.out.println("Woah, you beat the thug; but now the thug is angry and he won't rest until he beats you.");
                Thread.sleep(1000);
                thugloop = true;
                  System.out.println("Pick your numbers again");
                while(thugloop = true){

                    o4=reader.nextInt();
                o5=reader.nextInt();
                o6=reader.nextInt();
                o7=reader.nextInt();
                o8=reader.nextInt();
                int sumhop2 = o4+o5+o6+o7+o8;
                  int angrythug= 3 + (int)(Math.random()*85); 

                  if(sumhop2>angrythug){
                      Thread.sleep(1000);
                      System.out.println("Woah, you are really good at this!");
                       System.out.println("But the thug is getting angrier. Put in 5 more numbers:");
                         o4=reader.nextInt();
                o5=reader.nextInt();
                o6=reader.nextInt();
                o7=reader.nextInt();
                o8=reader.nextInt();

      **sumhop2 = o5 + o5 + o7 + o8;
     angrythug= 3 + (int)(Math.random()*85);** 


                    }else if(sumhop2<angrythug){

                      //other code goes here.
           break;

                    }

                }

So it works the first time, but when it says "the thug is getting angrier. Put in 5 more.." and I put in 5 more numbers, nothing happens, it's just a blinking cursor there.

How can I fix this error?

Thanks!

Answer 1

Once you enter 5 more numbers, you reach the start of the loop, which requires 5 more numbers to be input. Hence the blinking cursor.

Perhaps the first 5 inputs should be requested before the loop begins :

            o4=reader.nextInt();
            o5=reader.nextInt();
            o6=reader.nextInt();
            o7=reader.nextInt();
            o8=reader.nextInt();
            int sumhop2 = o4+o5+o6+o7+o8;
            int angrythug= 3 + (int)(Math.random()*85); 
            while(thugloop == true) {
                if(sumhop2>angrythug){
                     Thread.sleep(1000);
                     System.out.println("Woah, you are really good at this!");
                     System.out.println("But the thug is getting angrier. Put in 5 more numbers:");
                     o4=reader.nextInt();
                     o5=reader.nextInt();
                     o6=reader.nextInt();
                     o7=reader.nextInt();
                     o8=reader.nextInt();

                     sumhop2 = o5 + o5 + o7 + o8;
                     angrythug= 3 + (int)(Math.random()*85);
                     ...

Answer 2

after the thug is getting angrier. Put in 5 more.. the thug is getting angrier. Put in 5 more.. you are accepting 5 values doing the calculation in angrythug then the if block exits you are back to while loop. So print your result after the 5 intake values in if block.

edit: or do :

while(sumhop2 > angrythug){
Thread.sleep(1000);
System.out.println("Woah, you are really good at this!");
System.out.println("But the thug is getting angrier. Put in 5 more numbers:");
            o4=reader.nextInt();
            o5=reader.nextInt();
            o6=reader.nextInt();
            o7=reader.nextInt();
            o8=reader.nextInt();

  **sumhop2 = o5 + o5 + o7 + o8;
 angrythug= 3 + (int)(Math.random()*85);** 
}
// for sumhop2 < angrythug code goes here

// above loop will exit when the angrythug is greater than sumhop2