Spring Data Mongo - 如何通过@DBRef字段的id进行查询

Question

I am new to Spring Data Mongo so I must be doing something wrong because I can't manage to execute such a simple query. This is my model:

@Document(collection="brands")
public class Brand{
    @Id
    private int id;

    private String name;
    ...
    //getters-setters
}

@Document(collection="models")
public class Model{
    @Id
    private int id;
    private String name;
    @DBRef
    private Brand brand;
    ...
    //getters-setters
}

I would like to get all models from a brand, so I implement the DAO as follows:

@Repository
public interface IModelDAO extends MongoRepository<Model, Integer>{
    @Query(value="{ 'brand.$id' : ?0 }")
    public List<Model> findByBrandId(Integer id);   
}

If I execute this mongodb query in the shell it works: db.modelss.find({ 'brand.$id' : 1 })

But, the Java application throws the following exception:

Caused by: java.lang.IllegalAccessError
at org.springframework.data.mapping.PropertyReferenceException.detectPotentialMatches(PropertyReferenceException.java:134)

Apparently it is looking for a field $id in Brand class, and since it doesn't exist it fails. So I change the query to the following, so that it navigates to the id field:

@Query(value="{ 'brand.id' : ?0 }")

Now, it doesn't throw an exception but it doesn't find anything in the DB.

Debugging the MongoTemplate.executeFindMultiInternal() method in can see that in

DBCursor cursor = null;
    try {
        cursor = collectionCallback.doInCollection(getAndPrepareCollection(getDb(), collectionName));

cursor's query is query={ "brand" : 134} . So it makes sense it doesn't find anything. Changing the query value during debugging to query={ "brand.$id" : 134} it works.

So, why isn't the query correctly translated?

Answer 1

The problem was caused by the @Id int type. Changing it to Integer solved it:

@Document(collection="brands")
public class Brand{
    @Id
    private Integer id;

    private String name;
    ...
    //getters-setters
}

@Document(collection="models")
public class Model{
    @Id
    private Integer id;
    private String name;
    @DBRef
    private Brand brand;
    ...
    //getters-setters
}

Answer 2

try this;

Query que = new Query();
que.addCriteria(Criteria.where("user.$id").is(new ObjectId("123456789012345678901234")));